16 is the answer to this question.
Answer:
idk but you should lesten to blinding lights
Step-by-step explanation:
Simplify the following using a Property of Integer Exponents.
2,345⁰
2 + 5 = 7...it’s basic addition but ok...
Answer:
Altitude of the plane is 0.5 miles.
Step-by-step explanation:
From the figure attached,
An airplane A is at height h miles observes a small airstrip at D and a factory at F, 4.8 miles apart from D.
Angle of depressions for the airstrip is 13.1° and the factory is 4.1°.
We have to calculate the airplane's altitude h.
From ΔABF,
tan4.1 = ![\frac{AB}{BF}=\frac{h}{(x+4.8)}](https://tex.z-dn.net/?f=%5Cfrac%7BAB%7D%7BBF%7D%3D%5Cfrac%7Bh%7D%7B%28x%2B4.8%29%7D)
h = 0.07168(x + 4.8) -----(1)
From ΔABD,
tan13.1 = ![\frac{h}{x}](https://tex.z-dn.net/?f=%5Cfrac%7Bh%7D%7Bx%7D)
h = 0.2327x -----(2)
From equation (1) and (2),
0.07168(x + 4.8) = 0.2327x
0.2327x - 0.07168x = 4.8×0.07168
0.161x = 0.344
x =
miles
From equation (2),
h = 0.2327×2.137
h = 0.4972 miles
h ≈ 0.5 miles
Therefore, 0.5 miles is the altitude of the plane.
Number 5 would be D i think