Question

How to do this? Please help

Answer 1

Step-by-step explanation:

This equations are quadratic equations, which is on standard form,

${ax}^{2} + bx + c$

where a is the leading coefficient, b is the second coefficient, and c is the constant.

Both a and b are in quadratic equation so we need to find the constant separately.

Both sides are equal to zero so we can just subtract the terms not containing a or b in them to the opposite side.

${x}^{2} - 4 x + a = 0$

${x}^{2} + a = 4x$

$a = - {x}^{2} + 4x$

For b,

$2 {x}^{2} - 6x + b + 7 = 0$

$- 6x + b + 7 = - 2 {x}^{2}$

$b + 7 = - 2 {x}^{2} + 6x$

$b = - 2 {x}^{2} + 6x - 7$