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Delicious77 [7]
3 years ago
14

How much would the account earn in 1 year of simple interest at a yearly rate of 2.33%? Round to the nearest cent.

Mathematics
1 answer:
serg [7]3 years ago
3 0

Answer:

who knows what is the whole question

Step-by-step explanation:

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1 - 2³ - 3² 1 please answer correctly please
Bas_tet [7]

Answer:

-16

Step-by-step explanation:

1 - 8 - 9 = - 16

8 0
3 years ago
Approximately how many centimeters are in 54 ft?
dedylja [7]

Answer:

d) 54 ft = 1645.92 cm

Step-by-step explanation:

Given  : 54 ft.

To find : Approximately how many centimeters are in 54 ft.

Solution : We have given 54 ft.

We know

1 ft = 30.48 cm .

54 ft = 54 * 30.48 cm.

54 ft = 1645.92 cm.

Therefore, d) 54 ft = 1645.92 cm.

5 0
3 years ago
I dont understand if anybody can help me i would be happy​
SCORPION-xisa [38]

Answer:

  • (2, 3)

Step-by-step explanation:

<u>The rule for this dilation is:</u>

  • (x, y) → (x/2, y/2)

<u>Apply this rule to point B(4, 6):</u>

  • B(4, 6) → B'(2, 3)
4 0
3 years ago
Read 2 more answers
Determine any asymptotes (Horizontal, vertical or oblique). Find holes, intercepts and state it's domain.
vesna_86 [32]

Factorize the denominator:

\dfrac{x^2-4}{x^3+x^2-4x-4}=\dfrac{x^2-4}{x^2(x+1)-4(x+1)}=\dfrac{x^2-4}{(x^2-4)(x+1)}

If x\neq\pm2, we can cancel the factors of x^2-4, which makes x=-2 and x=2 removable discontinuities that appear as holes in the plot of g(x).

We're then left with

\dfrac1{x+1}

which is undefined when x=-1, so this is the site of a vertical asymptote.

As x gets arbitrarily large in magnitude, we find

\displaystyle\lim_{x\to-\infty}g(x)=\lim_{x\to+\infty}g(x)=0

since the degree of the denominator (3) is greater than the degree of the numerator (2). So y=0 is a horizontal asymptote.

Intercepts occur where g(x)=0 (x-intercepts) and the value of g(x) when x=0 (y-intercept). There are no x-intercepts because \dfrac1{x+1} is never 0. On the other hand,

g(0)=\dfrac{0-4}{0+0-0-4}=1

so there is one y-intercept at (0, 1).

The domain of g(x) is the set of values that x can take on for which g(x) exists. We've already shown that x can't be -2, 2, or -1, so the domain is the set

\{x\in\mathbb R\mid x\neq-2,x\neq-1,x\neq2\}

8 0
3 years ago
Which monomials are divisible by 5x
ValentinkaMS [17]
What is a monomials again?
7 0
3 years ago
Read 2 more answers
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