We have that
<span>triangle ABC
where
A(-5, 5), B(1, 1), and C(3, 4) are the vertices
using a graph tool
see the attached figure
the hypotenuse is the segment AC
find the equation of the line AC
</span>A(-5, 5) C(3, 4)
<span>
step 1
find the slope m
m=(y2-y1)/(x2-x1)-----> m=</span>(4-5)/(3+5)-----> m=-1/8
step 2
with C(3,4) and m=-1/8
find the equation of a line
y-y1=m*(x-x1)-----> y-4=(-1/8)*(x-3)----> y=(-1/8)*x+(3/8)+4
y=(-1/8)*x+(3/8)+4----> multiply by 8----> 8y=-x+3+32
8y=-x+35
the standard form is Ax+By=C
so
x+8y=35
A=1
B=8
C=35
the answer isx+8y=35
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Answer:
7.5
Step-by-step explanation:
Answer:
x = 3, x = 0
Step-by-step explanation:
To solve these factored equations, just divide each part by zero and solve.
2x(x-3) = 0 → (x-3) = 0, and 2x = 0.
(x-3) = 0 → x - 3 + 3 = 0 + 3 → <u>x = 3.</u>
2x = 0 → 2x/2 = 0/2 → <u>x = 0.</u>
Answer: D
3x^2 - 6x + 20 - 62/x + 3
Hope this helps! :)