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iragen [17]
3 years ago
10

What should be added to 780629 so that the sum is exactly divisible by 493?​

Mathematics
2 answers:
Leokris [45]3 years ago
7 0

Answer:

283

Step-by-step explanation:

Given problem is based on divisibilityy,

 = 780629/493

quotient = 1583

remainder = 210

So,Add 283 with remainder (210) to get 493

= 283+210

= 493

There for 283 should be added to 780629 so that the sum is exactly divisible by 493

babymother [125]3 years ago
5 0

The problem has come from division .

First divide them

\\ \sf\longmapsto \dfrac{480629}{493}

\\ \sf\longmapsto Remainder=210

\\ \sf\longmapsto Quiotent=1583

Now We have to add x to the remainder by which it will be 493

\\ \sf\longmapsto x+210=493

\\ \sf\longmapsto x=493-210

\\ \sf\longmapsto x=283

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