Answer:
i think it would be (B)
Step-by-step explanation:
Easy question
x=10
mECH=40
mHCD=50
mGCF=40
mECG=140
mGCD=13
<em><u>Hence</u></em><em><u> </u></em><em><u>we</u></em><em><u> </u></em><em><u>found</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>solution</u></em><em><u>.</u></em>
Equipment = 10%
Fees = 74%
Transportation = 16%
<span> divide a polynomial p(x) by (x-3). Add and subtract the multiple of (x-3) that has the same highest-power term as p(x), then simplify to get a smaller-degree polynomial r(x) plus multiple of (x-3). </span>
<span>The multiple of (x-3) that has x^4 as its leading term is x^3(x-3) = x^4 - 3x^3. So write: </span>
<span>x^4 + 7 = x^4 + 7 + x^3(x - 3) - x^3(x - 3) </span>
<span>= x^4 + 7 + x^3(x - 3) - x^4 + 3x^3 </span>
<span>= x^3(x - 3) + 3x^3 + 7 </span>
<span>That makes r(x) = 3x^3 + 7. Do the same thing to reduce r(x) by adding/subtracting 3x^2(x - 3) = 3x^3 - 9x^2: </span>
<span>= x^3(x - 3) + 3x^3 + 7 + 3x^2(x - 3) - (3x^3 - 9x^2) </span>
<span>= x^3(x - 3) + 3x^2(x - 3) + 9x^2 + 7 </span>
<span>Again to reduce 9x^2 + 7: </span>
<span>= x^3(x - 3) + 3x^2(x - 3) + 9x^2 + 7 + 9x(x - 3) - (9x^2 - 27x) </span>
<span>= x^3(x - 3) + 3x^2(x - 3) + 9x(x - 3) + 27x + 7 </span>
<span>And finally write 27x + 7 as 27(x - 3) + 88; </span>
<span>x^4 + 7 = x^3(x - 3) + 3x^2(x - 3) + 9x(x - 3) + 27(x - 3) + 88 </span>
<span>Factor out (x - 3) in all but the +88 term: </span>
<span>x^4 + 7 = (x - 3)(x^3 + 3x^2 + 9x + 27) + 88 </span>
<span>That means that: </span>
<span>(x^4 + 7) / (x - 3) = x^3 + 3x^2 + 9x + 27 with a remainder of 88</span>
Answer:
- 3
Step-by-step explanation:
3 times the sum of 5 and 4 is subtracted from 30
i.e.,
3 × (5 + 4) - 30
3 × 9 - 30
27 - 30 = - 3
Thus, 3 times the sum of 5 and 4 is subtracted from 30 is equal to -3
<u>-TheUnknown</u><u>Scientist</u>