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slavikrds [6]
3 years ago
7

Evaluate \dfrac14c+3d

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:45/2

Step-by-step explanation:.

Crank3 years ago
5 0

Answer:  \frac{45}{2}

Step-by-step explanation:

<h3> The exercise is: " Evaluate \frac{1}{4}c + 3d when c = 6 and   d = 7</h3>

Given the following expression:

 \frac{1}{4}c + 3d

You can follow these steps in order to evaluate it:

 1. Substitute c = 6 and   d = 7 into the expression provided in the exercise:

  \frac{1}{4}(6) + 3(7)

2. Solve the multiplications. Remember that:

 \frac{a}{b}*\frac{c}{d}=\frac{ac}{bd}

Then:

 =\frac{6}{4} +21

3. Reduce the fraction. Notice that the numerator 6 and the denomiantor 4 can be both divided by 2. Then:

=\frac{3}{2} +21

4. Solve the addition:

=\frac{3}{2} +\frac{21}{1}

 Since the number 21 has a denominator 1, the Least Common Denominator is:

LCD=2

Then, the sum is:

=\frac{3+42}{2}=\frac{45}{2}

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We are promoting a new book. The price was originally set at $26 and an average of 825 books were sold monthly. After research,
NARA [144]

Answer:

Step-by-step explanation:

The price that will maximize sales and the number of projected sales can be found in the vertex of a quadratic equation.  We need to use the puzzle of the info given to somehow create a set of biomials that can be multiplied together to get this quadratic.  We will separate the number of books sold from the price of the books in a table of sorts:

                # of books                              $ per book

We know that a number of 825 books was sold when the price per book was $26.

                # of books                             $ per book

                      825                                       $26

If we have a $1 decrease in price per book, let's use as our unknown the number of $1 decreases in price per book.  In other words, x = # of $1 decreases.  

If we decrease the price per book by $1, we are decreasing the price by 1x which is 1 dollar.

If, when we decrease the price per book by $1, we are selling the original 825 books plus another 75 books at the $1 decrease per book.  Now we have in our table

              # of books                             $ per book

               825 + 75x                                  26 - x

Under # of books, the expression in words says, "we are still selling 825 books, but now we are adding an additional 75 books per month when we lower the cost $1 per book".

Under $ per book, the expression in words says, "the cost per book is the starting cost minus $1".

To get the quadratic that results from this, multiply the 2 expressions together to get

P(x)=-75x^2+1125x+21450 or, if we want to keep things positive:

P(x)=75x^2-1125x-21450

We can factor a 75 out of each term to make the numbers a bit smaller:

P(x)=75(x^2-15x-286)

Use the quick formulas for h and k to solve for the vertex.  You could complete the square to get there, but once you know these formulas, there's no need to go through the very long long process of completing the square.

h=-\frac{b}{2a} and k=c-\frac{b^2}{4a}

These formulas come from the quadratic equation.  h here will give us the number of $1 decreases we need to maximize k, the profit from this amount decreases.

Our a = 1, b = -15 and c = -286.  Filling in for h:

h=-\frac{-15}{2} and

h=\frac{15}{2} so

h = 7.5  That is the number of decreases

Filling in for k:

k=-286-\frac{(-15)^2}{4} and

k=-286-\frac{225}{4} so

k = 342.25  That is the maximum projected sales from this amount of decreases in price.  

But we are not done.  We need to use the 7.5 to find out what the best price would be to maximize the sales and therefore, the profit.  Going back to our cost expression, 26 - x, using 7.5 for x:

26 - 7.5 = $18.50

This means that if we sell books at $18.50 rather than $26, we can expect to earn $342.25 per month in book sales.

4 0
3 years ago
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