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slavikrds [6]
3 years ago
7

Evaluate \dfrac14c+3d

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0

Answer:45/2

Step-by-step explanation:.

Crank3 years ago
5 0

Answer:  \frac{45}{2}

Step-by-step explanation:

<h3> The exercise is: " Evaluate \frac{1}{4}c + 3d when c = 6 and   d = 7</h3>

Given the following expression:

 \frac{1}{4}c + 3d

You can follow these steps in order to evaluate it:

 1. Substitute c = 6 and   d = 7 into the expression provided in the exercise:

  \frac{1}{4}(6) + 3(7)

2. Solve the multiplications. Remember that:

 \frac{a}{b}*\frac{c}{d}=\frac{ac}{bd}

Then:

 =\frac{6}{4} +21

3. Reduce the fraction. Notice that the numerator 6 and the denomiantor 4 can be both divided by 2. Then:

=\frac{3}{2} +21

4. Solve the addition:

=\frac{3}{2} +\frac{21}{1}

 Since the number 21 has a denominator 1, the Least Common Denominator is:

LCD=2

Then, the sum is:

=\frac{3+42}{2}=\frac{45}{2}

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