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AnnyKZ [126]
3 years ago
8

People are likely to pay less for an item during a shortage. True False

Advanced Placement (AP)
2 answers:
Irina-Kira [14]3 years ago
8 0
If a shortage exists, price must rise in order to entice additional supply and reduce quantity demanded until the shortage is eliminated.
kodGreya [7K]3 years ago
4 0

Answer:

False

Explanation:

If the supply for something is low and demand is high, the price will increase.

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I have 103 points should i juss give them all away?
RoseWind [281]

Answer:

OK give all the points away

5 0
3 years ago
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A ball is thrown into the air at a velocity of 44 feet per second. Its height in feet, h after t seconds is represented by the e
Lady_Fox [76]

Answer:

0.447 sec

Explanation:

velocity = distance/ time

distance 'h' is a function of time 't' given by

h = 12t^{2} + 44t + 16

⇒ differentiating equation

⇒ velocity = \frac{dh}{dt} = 24t + 44

⇒ acceleration = \frac{d^{2}h }{dt^{2} } = 24 \frac{ft}{sec^{2} }

deceleration due to gravity = -9.8 m/sec^{2} =  - 9.8 x 3.281 = - 32.154 ft/ sec^{2}

Net deceleration = 24 - 32.154 = - 8.15 ft/ sec^{2}

at maximum height v = 0

v^{2} = u^{2} + 2ah

⇒  0 = 44^{2} + 2 (-8.15)h

⇒ h = 118.72 ft⇒

118.72 = 12t^{2} + 44t + 16

⇒ 12t^{2} +44t - 102.72 = 0

⇒  t = -44 ± \sqrt{44^{2} - 4(12)(102.72) }     / (2 x 12)

t = 0.447 sec

6 0
3 years ago
When a star burns its fuel at a faster rate, late in its life, the extra energy flow causes what to happen?
Scilla [17]

Answer:

  The outer layer of the star expands

Explanation:

Late in life, when the hydrogen fuel for nuclear fusion is exhausted, the core of the star tends to collapse. That process generates heat that pushes the outer layers of the star outward.

The outer layer of the star expands.

4 0
3 years ago
What does hark the herald angels sing?
frez [133]
"Hark. The Herald Angles sing" That's the song. It was written by Charles Wesly 1739. An amazing Christmas carol tho. 
8 0
3 years ago
What is the total surface area of the figure below?
erica [24]

\bold{\huge{\pink{\underline{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>given </u><u>one </u><u>irregular </u><u>figure </u><u>which </u><u>is </u><u>composed </u><u>2</u><u> </u><u>triangle's </u><u>and </u><u>3</u><u> </u><u>rectangles </u>
  • <u>The </u><u>height </u><u>and </u><u>base </u><u>of </u><u>the </u><u>triangles</u><u> </u><u>is </u><u>6cm </u><u>and </u><u>7</u><u> </u><u>cm</u><u> </u><u>each </u>
  • <u>The </u><u>length </u><u>and </u><u>breath </u><u>of </u><u>the </u><u>rectangles</u><u> </u><u>is </u><u>1</u><u>3</u><u>.</u><u>1</u><u> </u><u>cm </u><u>and </u><u>7cm </u><u>each </u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>total </u><u>surface </u><u>area </u><u>of </u><u>the </u><u>given </u><u>figure</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

<u>We </u><u>have</u><u>, </u>

  • 2 triangles of height 6 cm and base 7cm each
  • 3 rectangles of length 13.1 cm and 7cm each

<u>Therefore</u><u> </u><u>,</u>

<u>We </u><u>know </u><u>that</u><u>, </u>

Area of triangle

\bold{=}{\bold{\pink{\dfrac{1}{2}}}}{\bold{\pink{ × Base × Height }}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

<u>Area </u><u>of </u><u>1</u><u> </u><u>triangle </u>

\sf{=}{\sf{\dfrac{1}{2}}}{\sf{ × 7 × 6 }}

\sf{ = 7 × 3 }

\sf{ = 21 cm²}

<h3><u>Therefore</u><u>, </u></h3>

<u>Area </u><u>of </u><u>2</u><u> </u><u>triangle's </u>

\sf{ = 2 × ( Area\:of\:1\:traingle) }

\sf{ = 2 × 21 }

\sf{ = 42 cm² }

Thus, The area of 2 triangles is 42 cm²

<h3><u>Now</u><u>, </u></h3>

<u>We </u><u>know </u><u>that</u><u>, </u>

Area of rectangle

\bold{\red{ = Length × Breath }}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

Area of 1 rectangle

\sf{ = 13.1 × 7 }

\sf{ = 91.7 cm² }

<h3><u>Therefore</u><u>,</u></h3>

<u>Area </u><u>of </u><u>3</u><u> </u><u>rectangles </u>

\sf{ = 3 ×( Area\:of\:1\:rectangle)  }

\sf{ = 3 × 91.7 }

\sf{ = 275.1 cm² }

Thus, The area of 3 rectangle is 275.1 cm²

<h3><u>So</u><u>, </u></h3>

Total area of the given figure

  • = Area of 2 triangles + Area of 3 rectangles

\sf{ = 42 + 275.1 }

\bold{ = 317.1 cm²}

Hence, The total surface area of the given figure is 317.1 cm² .

3 0
2 years ago
Read 2 more answers
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