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Umnica [9.8K]
3 years ago
7

Circles in the Coordinate Plane Acellus Complete the equation of this circle: А 1

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Answer:

(x -+2)² + (y - 4)² = 36

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k ) = (- 2, 4) and r = 6 , then

(x - (- 2))² + (y - 4)² = 6² , that is

(x + 2)² + (y - 4)² = 36 ← equation of circle

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Laura’s printer takes 5 minutes to print 85 pages.
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Answer:

17.

Step-by-step explanation:

<u>Divide 85 by 5 to find the unit rate:</u>

<u />\frac{85}{5} =17

17 represents the amount of pages printed for 1 minute.

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2 years ago
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Mr. Barnett’s test is normally distributed with a mean of 65 with a standard deviation of five points what is the probability th
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Answer: 2.5%

Step-by-step explanation:

Mean score = 65

Standard deviation = 5

Score (x) = >75

Z-score = [(score - mean) ÷ standard deviation]

Z - score = [(75 - 65) ÷ 5]

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2 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

(a)

The bid should be greater than $10,000 to get accepted by the seller. Let bid x be a continuous random variable that is uniformly distributed between

$10,000 and $15,000

The interval of the accepted bidding is [ {\rm{\$ 10,000 , \$ 15,000}], where b = $15000 and a = $10000.

The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}

=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4

(b)  The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)

=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8

(c)

The amount that the customer bid to maximize the probability that the customer is getting the property is calculated as,  

The interval of the accepted bidding is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The interval of the given bidding is [$10,000,$15,000].

\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}

(d)  The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.

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3 years ago
What is log base 5(4*7 )+log base 5 of 2 written as a single log?
nataly862011 [7]
The answer for the exercise shown above is the last option (Option D), which is:

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The explanation is show below:

 1. You have the following logarithm expresssion:

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</span>
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 3. Therefore, as you can see, the answer is the option mention before.
 
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