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Given a cube of sides 4 units with vertices: A, B, C, D, E, F, G, H such that the top square is ABCD and the bottom square is EFGH with AC, BD the diagonals of the top square and EG, FH the diagonals of EFGH.
The shape of the cross-section formed when a plane containing line AC and line EH intersects the cube is the rectangle ACEH.
We obtain the value of line AC which is equal to line EH using the pythagoras rule which states that
, where c is the length of line AC, a is the length of line AB = 4 and b is the length of line BC = 4.
Thus,
Therefore, the shape of the cross-section formed when a plane containing line AC and line EH intersects the cube is the rectangle ACEH with length of
units and width of 4 units.
Area of a rectangle is given by
Area = length x width
square units.
The shape of the cross-section formed when a plane containing line AC and line EH intersects the cube is the rectangle ACEH.
We obtain the value of line AC which is equal to line EH using the pythagoras rule which states that
Thus,
Therefore, the shape of the cross-section formed when a plane containing line AC and line EH intersects the cube is the rectangle ACEH with length of
Area of a rectangle is given by
Area = length x width
Answer:
35
Step-by-step explanation:
Answer:
Area of shaded region = 119.44 cm²
Step-by-step explanation:
Area of circle = πr²
= 3.14 × 2²
= 3.14 × 2 ×2
= 12.56 cm²
Area of rectangle = length × breadth
= 11cm × 12cm
= 132 cm²
Area of shaded region = Area of rectangle - Area of circle
= (132 - 12.56) cm²
= 119.44 cm²
