Multiply 631.6 by 0.8

leva [86]

Algebraically, that will be expressed as:

$3n +7$

7 0

3 years ago

8 kg of potatoes and 5 kg of carrots cost $28 whereas 2 kg of potatoes and 3 kg of carrots cost $11.20.what is the cost of 1 kg

spin [16.1K]

Potatoes (kg) Carrots (kg) Cost($)
8 5 28
2 3 11.20

8 0

3 years ago

Please someone help me out here!! I Will Mark the right one Brainiest!!!!but hurry please

mars1129 [50]

Answer:

Step 2

Step-by-step explanation:

During step 2, when dividing by 4 on both sides, Jessica got -16 / 4 was 4, which is not true. Basically she switched the sign when she shouldn't have.

6 0

3 years ago

The power generated by an electrical circuit (in watts) as a function of its current ccc (in amperes) is modeled by: P(c)=-12c^2

g100num [7]

Answer:

5 amperes will produce the maximum power of 300 watts.

Step-by-step explanation:

The general form of a quadratic function presents the function in the form

$f(x)=ax^2+bx+c$

The vertex of a quadratic function is the highest or lowest point, also known as the maximum or minimum of a quadratic function.

We can define the vertex by doing the following:

Identify a, b, and c
Find, the x-coordinate of the vertex, by substituting a and b into

$x-coordinate =-\frac{b}{2a}$

Find, the y-coordinate of the vertex, by evaluating

$y-coordinate =f(x-coordinate )=f(-\frac{b}{2a} )$

We know that the power generated by an electrical circuit is modeled by

$P(c)=-12c^{2}+120c$

This function is a quadratic function.

To find the current that produce the maximum power you must

Identify a and b

a = -12 and b = 120

Find, the maximum current of the vertex, by substituting a and b into

$maximum-current =-\frac{b}{2a}$

$maximum-current =-\frac{120}{2(-12)}\\\\maximum-current = 5$

Find, the maximum-power, by evaluating

$maximum-power =P(maximum-current)=P(-\frac{b}{2a} )$

$P(5)=-12(5)^{2}+120(5)=300$

5 amperes will produce the maximum power of 300 watts.

We can check our work with the graph of the function $P(c)=-12c^{2}+120c$ and see that the maximum is (5, 300).

5 0

4 years ago

I WILL MARK BRAINLIEST PLEASE HELP FIND ANGLE DEB ITS DUE AT 12 PLEASE HELP PLEASE

Gemiola [76]

Answer:

$\boxed {\boxed {\sf \angle DEB = 111 \textdegree}}$

Step-by-step explanation:

We want to find angle DEB. We know AB is perpendicular to AC, CD is congruent to CE and angle B is 48 degrees.

ABC is a triangle. The angles in a triangle must add up to 180 degrees. Therefore:

∠A+∠B+∠C= 180°

We know two angles: ∠B= 48° and ∠A= 90° (the little square denotes a right angle).

90°+48°+ ∠C= 180° Substitute values in.

138°+ ∠C =180° Add
138°-138° ∠C= 180°-138° Subtract 138 from both sides.
∠C= 42°

Note that angle C is part of another triangle. It is isosceles because the two legs (CD and CE) are congruent. Therefore, the two base angles (E and D) are congruent.

∠C+∠D+∠E= 180°
∠C+ 2∠D= 180° Angles D and E are congruent
42°+ 2∠D= 180° Substitute 42 in for angle C
42°-42° +2∠D= 180°-42° Subtract 42 from both sides.
2∠D= 138°
2∠D/2= 138°/2 Divide both sides by 2.
∠D= 69°

∠D and ∠E equal 69 degrees.

Angle CED (∠E) and DEB are on a straight line together. Therefore, they are supplementary and equal 180 degrees.

∠CED+ ∠DEB= 180
69° +∠DEB= 180° Substitute 69 for angle CED
69°-69° +∠DEB= 180°-69° Subtract 69 from both sides
∠DEB=111°

Angle DEB is equal to 111 degrees

8 0

3 years ago

Multiply 631.6 by 0.8​

Multiply 631.6 by 0.8