Answer:
7 cm
Step-by-step explanation:
SA = 208 cm^2
SA= 2*a*b + 2*a*c + 2*b*c
where:
a= first dimension = 2 cm
b= second dimension = 10 cm
c= third dimension
so we have:
208= 2*2*10 + 2*2*c + 2*10*c
208= 40 + 4c + 20c
208-40= 24c
168=24c
c =168/24
c = 7cm = third dimension
Answer:
x = 3/4
y = 2.5
Step-by-step explanation:
No there is just one.
Equate the ys
-2/3 x + 3 = 2/3 x + 2 Add 2/3 x to both sides
3 = 2/3 x + 2/3x + 2 Combine
3 = 4/3 x + 2 Subtract 2
3-2 = 4/3 x Multiply by 3
1 * 3 = 4x Divide by 4
3/4 = x
====================
y = 2/3 x + 2
y = 2/3 * 3/4 + 2
y = 6/12 + 2
y = 1/2 + 2
y = 2 1/2
y = 2.5
The answer is:
(1,4) into (5,2)
(3,1) into (7,-1)
(1,1) into (5,-1)
Answer:
the most they could weigh is .74 kilos and the least would be .62
Step-by-step explanation:
The magnification is 0.54
Given,
The distance between object and concave lens, u = -21 cm
Focal length of the concave lens, f = -25 cm
Let m be the magnification.
m = v/u
Here v is the position of image.
We have to find v first.
By using lens equation we can determine v.
That is,
1/f = 1/v – 1/u
So,
- (1/25) = 1/v – (-1/21)
- (1/25) = 1/v + 1/21
1/v = - (1/25) – 1/21
1/v = (-25 – 21) / (21 x 25)
1/v = - (46/525)
Therefore v = - (525/46)
v = -11.41 cm
Now we have to find magnification, m.
m = v/u
= (-11.41) / (-21)
= 0.54
Here magnification is 0.54
Learn more about concave lens here: brainly.com/question/12944945
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