Answer:
Wait what is the question the question you put in was
"PLEASE ANSWER ILL MAKE YOU BRAINLIEST 2 questions"
Step-by-step explanation:
Answer:
Hi there!
Your answers are:
1) x> 5
Some numbers that would fit this equation are 6, 7, 8, etc!
2) x<= 30
Some numbers that would fit this are 30, 29, 28, etc!
3) x>= 17
Some numbers that would fit this equation are 17, 18, 19, etc!
4) x>= 90
Some numbers that would fit this are 90, 91, 92, etc!
Hope this helps!
These are the steps, with their explanations and conclusions:
1) Draw two triangles: ΔRSP and ΔQSP.
2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).
3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.
4) The segment SP is common to both ΔRSP and Δ QSP.
5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.
Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q
Answer:
The speed of the cyclist is 10 miles per hour .
Step-by-step explanation:
Given as :
The distance cover by cyclist = 
= 20 miles
The distance cover by biker = 
= 6 miles
The speed of biker = 
= s mph
The speed of cyclist = 
= 7 + s mph
The time taken by both cyclist and biker = t hour
Now. Distance = Speed × Time
So, = × t
Or, 20 = s × t
Or, t = 
.....1
And ,
= × t
or, 6 = s t
Or, t = 
....2
From Eq 1 and 2
I.e =
Or, 20 s = 6 ( 7 + s )
Or, 20 s - 6 s = 42
Or, 14 s = 42
∴ s = 
I,e s = 3 miles per hour
So, The speed of biker = = s = 3 miles per hour
And The speed of cyclist = = 7 + s = 7 + 3= 10 miles per hour
Hence The speed of the cyclist is 10 miles per hour . Answer
We have that
<span>4x -2y =22------> clear variable y
2y=4x-22--------> y=4x/2-22/2---------> y=2x-11-----> equation 1
2x + 4y = 6------> equation 2
substitute equation 1 in equation 2
2x+4*[2x-11]=6-----> 2x+8x-44=6----> 10x=50------> x=5
then
y=2x-11----> y=2*5-11----> y=-1
</span>
