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Andrei [34K]
3 years ago
10

Express

title="(4 - x) {}^{ \frac{1}{2} } " alt="(4 - x) {}^{ \frac{1}{2} } " align="absmiddle" class="latex-formula">
in ascending power of x up to term x²

​
Mathematics
1 answer:
Kisachek [45]3 years ago
6 0

Answer:

Step-by-step explanation:

Remember:

\boxed{(1+y)^{\frac{1}{2} }= 1+\dfrac{y}{2} -\dfrac{y^2}{2*4} +\dfrac{1*3*y^3}{2*4*6} +K\ with -1 < y \leq  1 }\\\\\\Let\ say\ 4-x=1+y\ or\ y=3-x\\\\\\(4-x)^{\frac{1}{2} }=1+\dfrac{3-x}{2} -\dfrac{(3-x)^2}{2*4} +K\ with\ 2\leq x

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maksim [4K]

Answer:

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5 0
4 years ago
Can you help me plz .
Scilla [17]
Solve for x:(2 x + 3)/3 - 1 = 10
Put each term in (2 x + 3)/3 - 1 over the common denominator 3: (2 x + 3)/3 - 1 = (2 x + 3)/3 - (3)/3:(2 x + 3)/3 - (3)/3 = 10
(2 x + 3)/3 - (3)/3 = ((2 x + 3) - 3)/3:(-3 + 3 + 2 x)/3 = 10
Add like terms. 3 - 3 = 0:(2 x)/3 = 10
Multiply both sides of (2 x)/3 = 10 by 3/2:(3×2 x)/(2×3) = (3×10)/2
(3×10)/2 = (3×10)/2:(3×2 x)/(2×3) = (3×10)/2
(3×2 x)/(2×3) = (2×3)/(2×3)×x = x:x = (3×10)/2
10/2 = (2×5)/2 = 5:x = 3×5
3×5 = 15:Answer:  x = 15
8 0
4 years ago
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
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(A.

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In A, line AD straight into BC, thus creating two 90 degree angles. This means that they are perpendicular.

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8 0
2 years ago
What would the answer be
Hoochie [10]

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3 years ago
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