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tatiyna
3 years ago
6

Raman has two daughters deepa and anju.Present age of raman is nine more than that twice the sum of deepa and anju.Five years he

nce age of the raman is four more than one and half times the sum of age of deepa and anju.Find the age of the Raman.
Mathematics
1 answer:
Leya [2.2K]3 years ago
7 0
The age of the Raman is 9.
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-4 x f (8) + 3 x g(-7) HELP ASAP
lubasha [3.4K]

Answer:

-32

Step-by-step explanation:

-4 + f(8) + 3 x g(-7) = ?

To find f(8), look at each of the f(x) function and find x = 8. The y value is the answer you will plug in for f(8). The same goes for g(-7), but you will be looking at the g(x) function at x = -7.

f(8) = -4

g(-7) = -8

Make sure you solve in the correct order using PEMDAS.

-4 + (-4) + 3 x (-8) = -32

8 0
3 years ago
Clare has 54$ in her bank account. A store credits her account with a 10$ refund. How much does she now have in the bank?​
s2008m [1.1K]
Clare now has $64 in her bank account.

54 + 10 = 64
6 0
3 years ago
1.<br> Find the slope of the line.<br> Ay<br> a) -574<br> b) 5/4<br> c) -4/5<br> d) 4/5
maria [59]

Answer:

a) -5/4

Step-by-step explanation:

Slope is fundamentally rise/run; The points on the line are relative to each other by decreasing/increasing the y-value of +/-5 and decreasing/increasing the x-value by +/-4

The function is decreasing so the slope has to be negative.

The only possible answer choice is -5/4 or a.

3 0
3 years ago
What is the area of the figure?
zalisa [80]

Answer: 57 ft²

Step-by-step explanation:

Find the areas of the two individual rectangles and then add that up to find the area of the figure:

Rectangle A:                                                             Rectangle B:

= Length * Width                                                       = 11.5 * 3

= 7.5 * 3                                                                     = 34.5ft²

= 22.5 ft²

Area of figure:

= 22.5 + 34.5

= 57 ft²

3 0
3 years ago
Read 2 more answers
an ordered pair where the x and y coordinate are the same lies in the 1st or 3rd quadrant. true, sometimes true or not true?. ex
Zarrin [17]

The quadrants are as follows:

The 1st quadrant has the points which have both x and y positive and the 3rd quadrant has the points which have both x and y negative. If the ordered pair and the same x and y value, if ons is positive, the other also is, and the same for negative.

So, at first we see that there are point where the x and y are the same and that are in the 1st or 3rd quadrant.

However, there is one special case:

When x and y are 0, that is, the ordered pair is (0, 0).

Since this point is the origin, it doesn't lie on any of the quadrants.

Thus, this affirmative is sometimes true. Every point but (0, 0) that have same x and y values are in the 1st or 3rd quadrant except for (0, 0).

7 0
2 years ago
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