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tatiyna
3 years ago
6

Raman has two daughters deepa and anju.Present age of raman is nine more than that twice the sum of deepa and anju.Five years he

nce age of the raman is four more than one and half times the sum of age of deepa and anju.Find the age of the Raman.
Mathematics
1 answer:
Leya [2.2K]3 years ago
7 0
The age of the Raman is 9.
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Consider the quadratic equation ax^2+bx+5=0,where a, b and c are rational numbers and the quadratic has two distinct zeros.
FrozenT [24]
You have shared the situation (problem), except for the directions:  What are you supposed to do here?  I can only make a educated guesses.  See below:

Note that if    <span>ax^2+bx+5=0    then it appears that c = 5 (a rational number).

Note that for simplicity's sake, we need to assume that the "two distinct zeros" are real numbers, not imaginary or complex numbers.  If this is the case, then the discriminant,    b^2 - 4(a)(c), must be positive.  Since c = 5, 

b^2 - 4(a)(5) > 0, or b^2 - 20a > 0.

Note that if the quadratic has two distinct zeros, which we'll call "d" and "e," then 

(x-d) and (x-e) are factors of ax^2 + bx + 5 = 0, and that because of this fact,

         - b plus sqrt( b^2 - 20a )
d =  ------------------------------------
                      2a

and

 </span>         - b minus sqrt( b^2 - 20a )
e =  ------------------------------------
                      2a

Some (or perhaps all) of these facts may help us find the values of "a" and "b."  Before going into that, however, I'm asking you to share the rest of the problem statement.  What, specificallyi, were you asked to do here?

7 0
3 years ago
What is smaller...<br> 3/10<br> 0.4<br> 35%
VMariaS [17]
Convert all of them in decimals

3 ÷ 10 = 0.3

0.4

35% ÷ 100 = 0.35

Order from least to greatest--

3/10, 35%, 0.4

3/10 is the smallest 
7 0
3 years ago
Read 2 more answers
14. Let R^2 have inner product defined by ((x1,x2), (y,, y2)) 4x1y1 +9x2y2 A. Determine the norm of (-1,2) in this space B. Dete
Vitek1552 [10]

The norm of a vector \vec x is equal to the square root of the inner product of \vec x with itself.

a. \|(-1,2)\|=\sqrt{\langle(-1,2),(-1,2)\rangle}=\sqrt{4(-1)^2+9(2)^2}=\sqrt{40}=2\sqrt{10}

b. \|(3,2)\|=\sqrt{\langle(3,2),(3,2)\rangle}=\sqrt{4(3)^2+9(2)^2}=\sqrt{72}=6\sqrt2

7 0
3 years ago
Writetwo ways you could use to find 5+8
Igoryamba

5+8=13

or

13-8=5

Hope this helps!

5 0
3 years ago
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What is the area of this isosceles trapezoid 96 60 48 72
Lelechka [254]

Step-by-step explanation:

s3d4drks3ks2srddex5v5

4 0
3 years ago
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