Answer:
2x^4-11x^3+68x-80
2x^4-4x^3-7x^3+14x^2-14x^2+28x+40x-80
2x^3(x-2)-7x^2(x-2)-14x(x-2)+40(x-2)
(x-2)(2x^3-7x^2-14x+40)
(x-2)(2x^3-4x^2-3x^2+6x-20x+40)
(x-2)(2x^2(x-2)-3x(x-2)-20(x-2))
(x-2)(x-2)(2x^3-3x-20)
(x-2)(x-2)(2x^2+5x-8x-20)
(x-2)(x-2)(x(2x+5)-4(2x+5))
(x-2)(x-2)(2x+5)(x-4)
(x-2)^2(2x+5)(x-4)
Divide the area by the number in the triangle
I believe it’s c ^^
since you multiply the numerators and denominators.. so since the first fraction is 1/2 & the second is 3/4, you’d multiply it like:
1 x 3 & 2 x 4, giving you 3/8.
-5= -5x-10
Plus 10 from both sides
5=-5x
X = -1
