X^2 + 10x + 11 = 0
x^2 + 10x = -11
x^2 + 10x + 25 = -11 + 25
(x + 5)^2 = 14 <===
x + 5 = (+-) sqrt 14
x = -5 (+-) 3.74
x = -5 + 3.74 = -1.26 <== solution
x = -5 - 3.74 = - 8.74 <== solution
1)44
3)44
4)136
i want to say that the other side 5-8 are the same as 1-4 but im not totally sure
<h3>
Answer: 7m+30</h3>
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Work Shown:
3(m+2) + 4(6+m)
3m+6 + 24 + 4m
(3m+4m) + (6+24)
7m+30
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Explanation:
In the second step, I used the distribution rule a*(b+c) = a*b+a*c. We multiply the outer term by every term inside. So for instance 3(m+2) = 3*m+3*2 = 3m+6. A similar situation applies to 4(6+m) as well. Afterward, I grouped and combined like terms.
We can think of 3m+4m = 7m as saying "I have 3 maps and someone gave me 4 more maps, so that means I have 3+4 = 7 maps now". The m is a place holder for any number.
Answer:
52metre
Step-by-step explanation:
Let us use proportion in solving this question, the land has a scale of 1 1/4 cm to 3 1/4 m then the proportion is
( 1 1/4)/ (3 1/4 ) =[blueprint of the plot of land/length of the actual peace of land]
But we need to convert those mixed fractions to improper fraction for easy simplification
1 1/4= [(4×1)+4]= 5/2
3 1/4=[(4×3)+1)]=13/4
Then we can proceed with simplification as
(5/2)/(13/4)=[blueprint of the plot of land/length of the actual peace of land]
But we were given length of the actual peace of land as 20 cm, then
(5/2)/(13/4)=[blueprint of the plot of land/20]
If we cross multiply we have
[blueprint of the plot of land] ×13/4 =5/2 ×20
[blueprint of the plot of land] =(5/2 ×20)÷(13/4)
= 50/(13/4)
=(4×13)/50
= 52
Therefore, the length of the actual peace of land is 52metre
Answer:
Step-by-step explanation: