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3 years ago

Find the 98th term of the arithmetic sequence 14, 10, 6, ...

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

8 0

Answer:

Brainliest!!!!

Step-by-step explanation:

the equation is this...

y = -4x + 14

97 x -4 = -388

-388 + 14 = -374

<em>you might wonder why I did 97... that is becuase 14 is the first term</em>

topjm [15]3 years ago

6 0

Answer:

-374

Step-by-step explanation:

We know that a₁ = 14 and the common difference = -4 so the explicit rule is aₙ = 14 + (n - 1) * (-4) = -4n + 18. a₉₈ = -4 * 98 + 18 = -374.

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15 people are expected for a dinner. Three ounces of corn serves one person. A can of corn is nine ounces. How many cans of corn

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5 cans need to be bought. There are three servings in each can so you divide 15 by 3.

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3 years ago

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Write the Arabic value of MDCCXLIV

iris [78.8K]

M = 1,000

D = 500

C = 100

L = 50

X = 10

V = 5

I = 1

MDCCXLIV

M = 1,000

DCC = 500 + 100 + 100 = 700 (smaller after larger, then adding)

XL = 50 - 10 = 40 (smaller before bigger, then subtraction)

IV = 5 - 1 = 4 (smaller before bigger, then subtraction)

<h3>MDCCXLIV = 1,000 + 700 + 40 + 4 = 1,744</h3>

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4 years ago

1. With the points

malfutka [58]

Answer:

B': (-12,15)

Step-by-step explanation:

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3 years ago

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. Illustra

Rainbow [258]

Answer:

$x = t$

$y = 1 - t$

$z = 2t$

Step-by-step explanation:

Given

$x=t$

$y=e^{-t}$

$z=2t-t^2$

(0, 1, 0)

The vector equation is given as:

$r(t) = (x,y,z)$

Substitute values for x, y and z

$r(t) = (t,\ e^{-t},\ 2t - t^2)$

Differentiate:

$r'(t) = (1,\ -e^{-t},\ 2 - 2t)$

The parametric value that corresponds to (0, 1, 0) is:

$t = 0$

Substitute 0 for t in r'(t)

$r'(t) = (1,\ -e^{-t},\ 2 - 2t)$

$r'(0) = (1,\ -e^{-0},\ 2 - 2*0)$

$r'(0) = (1,\ -1,\ 2 - 0)$

$r'(0) = (1,\ -1,\ 2)$

The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)

It should be noted that:

The equation of a line through position vector a and parallel to vector v is given as:

$r(t) = a + tv$

Such that:

$a = (0,1,0)$ and $v = r'(0) = (1,-1,2)$

The equation becomes:

$r(t) = (0,1,0) + t(1,-1,2)$

$r(t) = (0,1,0) + (t,-t,2t)$

$r(t) = (0+t,1-t,0+2t)$

$r(t) = (t,1-t,2t)$

By comparison:

$r(t) = (x,y,z)$ and $r(t) = (t,1-t,2t)$

The parametric equations for the tangent line are:

$x = t$

$y = 1 - t$

$z = 2t$

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3 years ago

13. One kilogram is equal to 1,000 grams.

Ilya [14]

Answer:

I'm pretty sure it's 0.257!

Step-by-step explanation:

Sorry if I got it wrong I'm trying my best hope you have a great day!!

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3 years ago

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