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3 years ago

6

Any recurring sequence of points above and below the trend line lasting less than one year can be attributed to the cyclical com

ponent of the time series.
a. True
b. False

1 answer:

kolezko [41]3 years ago

5 0

True because I took this text before

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What is the answer to #4 ?

jeyben [28]

R and s are parallel
m<2 = m<6
but m<6 + m<8 = 180
so
m<2 + m<8= 180

answer
B. m<2 + m<8= 180

6 0

4 years ago

The center field wall at Angel Stadium is 390 feet from home plate. If Mrs Martinez was playing

yuradex [85]

Answer:

yes she did make a home run

Step-by-step explanation:

because, doing the math she makes it there just in time

8 0

3 years ago

Select the best answer

VLD [36.1K]

Answer:

its d

Step-by-step explanation:

4 0

3 years ago

A jar contains 100 marbles. There are 10 blue marbles, 79 green marbles, 6 red marbles, and 5 yellow marbles. What is the probab

ad-work [718]

To find the probability of pulling something first take note of the total number and the amount of which you want to select.

100 and 10

Now set them up as a fraction

10/100 and simplify

1/10 or 10%

6 0

4 years ago

Consider the following sequence of numbers 3, -9, 27, -81, ….

lesya [120]

<u>QUESTION 1</u>

The given sequence is $3,-9,27,-81,...$ .

The first term of the sequence is $a_1=3$

The second term is $a_2=-9$

The common ratio can be found using any two consecutive terms of the sequence.

Thus, the common ratio is given by $r=\frac{a_n}{a_{n-1}}$ .

This implies that,

$r=\frac{-9}{3}$

This simplifies to,

$r=-3$

The correct answer is C

<u>QUESTION 2</u>

The sum of the first n terms of a geometric sequence is given by;

$S_n=\frac{a_1(r^n-1)}{r-1}$ .

Since we are looking for the first five terms, we substitute $n=5$ , $a_1=3$ and $r=-3$ into the formula to obtain,

$S_5=\frac{3((-3)^5-1)}{-3-1}$

This will evaluate to give us;

$S_5=\frac{3(-243-1)}{-3-1}$

$S_5=\frac{3(-244)}{-4}$

$\Rightarrow S_5=3\times 61$

$\Rightarrow S_5=183$

The correct answer is A

8 0

4 years ago

Read 2 more answers