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Aleks04 [339]
3 years ago
11

Bigger then, less then, or equal to? 1/8 0.125

Mathematics
2 answers:
Lerok [7]3 years ago
8 0
The answer is equal to
LekaFEV [45]3 years ago
7 0

1/8 is greater than 0.125


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Are the lines 2y-10x=4 and y-2=5x parallel ??
aleksandrvk [35]
Well,

If the slope of the lines are the same, then the lines are parralel.

We need to manipulate 2y - 10x = 4 into y = mx + b form.

Add 10x to both sides
2y = 10x + 4

Divide both sides by 2
y = 5x + 2

Do the same thing with the other equation.

Add 2 to both sides
y = 5x + 2

y = 5x + 2

It appears that, not only are they parallel, but they lie on exactly the same line! If this was a System of Simultaneous Linear Equations, then there would be an infinite number of solutions!<span />
5 0
4 years ago
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A certain colony of bacteria begin with one cell and the population doubles every 20 minutes. What was the population of The Col
svetoff [14.1K]
First 20 minutes:1 Second 20:2 Third 20:4 Fourth 20: 8. Fifth 20: 16 Sixth 20: 32. C is your answer
3 0
3 years ago
When p = 12, t = 2, and s = 1/6, r = 18. If r varies directly with p and inversely with the product of s and t, what is the cons
Ilia_Sergeevich [38]
R = kp/st
18 = 12k/(1/6 x 2)
18 = 12k/(1/3)
18 = 36k
k = 18/36 = 1/2

3 0
3 years ago
Prove the identity 2csc2x=csc^2xtanz
Verizon [17]

Step-by-step explanation:

Consider the LHS, after the 5th step, consider the RHS

2 \csc(2x)  =  \csc {}^{2} (x)  \tan(x)

2 \frac{1}{ \sin(2x) }  =  \csc {}^{2} (x)  \tan(x)

2  \times \frac{1}{2 \sin(x)  \cos(x) }  =  \csc {}^{2} (x)  \tan(x)

\frac{1}{ \sin(x) \cos(x)  }  =   \csc {}^{2} (x)  \tan(x)

\csc(x)  \sec(x)  =  \csc {}^{2} (x)  \tan(x)

Consider the RHS

\csc(x)  \sec(x)  =( 1 +  \cot {}^{2} (x) ( \tan(x))

\csc(x)  \sec(x)  =  \tan(x)  +  \cot(x)

\csc(x)  \sec(x)  =  \frac{ \sin(x) }{ \cos(x) }  +  \frac{ \cos(x) }{ \sin(x) }

\csc(x)  \sec(x)  =  \frac{1}{ \sin(x) \cos(x)  }

\csc(x)  \sec(x)  =  \csc(x)  \sec(x)

7 0
2 years ago
While on vacation in Canada, you notice that temperatures are reported in degrees Celsius. You know there is a linear
sashaice [31]

Since , the relation is linear .

Let equation is y = mx + c .

Putting , x = 0 and y = 32 .

32 = c  .......( 1 )

Also , putting x = 100 and y = 212 .

We get :

212 = 100m + c .......( 2 )

Comparing equation 1 and 2 .

100m = 212 - 32

x = 1.8

Therefore , y = 1.8x + 32 .

Hence , this is the required solution .

7 0
4 years ago
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