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nadezda [96]
3 years ago
6

Prove that is here

20%7B2%7D%20a" id="TexFormula1" title="1 - cos {2}a \div 1 - sin a{2} = tan {2} a" alt="1 - cos {2}a \div 1 - sin a{2} = tan {2} a" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
garri49 [273]3 years ago
8 0

\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}

<h3>LHS</h3>

\boxed{\sf \dfrac{cosA}{sinA}=cotA}

\\ \sf\longmapsto \dfrac{1-cos2A}{1-sin2A}

\\ \sf\longmapsto 1-cot2A

\\ \sf\longmapsto 1-\dfrac{1}{tan2A}

\\ \sf\longmapsto \dfrac{tan2A-1}{tan2A}

\\ \sf\longmapsto tan2A

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Six rectangles each with a common base width of 22 have lengths of 1,4,9,16,251,4,9,16,25, and 3636. What is the sum of the area
Firdavs [7]

The area of the rectangle is the product of the length and the width of the quadrilateral. Hence, the sum of the areas is equal to  $2*1+2*4+2*9+2*16+2*25+2*36$. This is simply equal to $2*(1+4+9+16+25+36)$, which is equal to $2*91$, which is equal to our final answer of 182.
6 0
3 years ago
Answers to this equation
Tju [1.3M]

Answer:

for completing the square it would be

(x + x) ^{2}  - 13

however if you were to find the roots it would

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3 years ago
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Paha777 [63]
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3 years ago
Slove for x<br> 3(2x-5)=4x+33
larisa [96]
3(2x - 5) = 4x + 33
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5 0
3 years ago
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swat32

Answer:

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Step-by-step explanation:

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4 years ago
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