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adelina 88 [10]
3 years ago
7

PLEASE ANSWER!!

Mathematics
1 answer:
Aleksandr [31]3 years ago
3 0

Answer: The true cost of the jacket is $27 dollars.

Step-by-step explanation: To find the cost of the jacket after the discount just do 30 X .1 to get 3. Then take 3 and subtract it from 30. The mistake the clerk made was he probably just saw 10% and did 30-10=20. The clerk might have brain damage because this is like 5th grade math.

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I think I have the answer, but would like to check my work
notsponge [240]

Notice that we can calculate the area of the square and the rectangle separately to get the following:

\begin{gathered} A_1=3\cdot3=9in^2 \\ A_2=9\cdot2=18in^2 \\ \Rightarrow A=A_1+A_2=9+18=27in^2 \end{gathered}

therefore, the total area is 27 in^2

4 0
1 year ago
Jackie wants to justify that f(x) = 2x - 6 is a linear function. If she evaluated F(x) for consecutive integer values, write a s
NISA [10]

Jackie wants to justify that f(x) = 2x - 6 is a linear function.

Lets assume some values for x  and find out f(x)

We make a table with x values 1, 2, 3, 4 and find f(x)

To find f(x) we plug in x  value in the given equation

x        f(x)

1          2(1)-6 = -4

2         2(2)-6 = -2

3          2(3)-6 = 0

14         2(4)-6 =2

for f(x) we got -4, -2, 0 , 2

The value of f(x) is increasing by 2. There is a constant increase in f(x)

When there is a constant rate of increase then it is a linear function

constant rate of increase that is slope = 2. Hence f(x) = 2x -6 is a linear function.



6 0
3 years ago
If: \qquad AC = 64 AB = 7x + 8, and BC= 3x+6, Find BC
Nady [450]

The answer is 21.

First you Add both AB and BC which is 10x +14. Then you put 64 into the equation. 10x+14=64. Subtract 14 from 64 which is 50. So 10x=50. Then divide 10 from 50. which would be x=5. So if you plug it in. It would be 21.

4 0
3 years ago
Pls help. i never understood this rule.
Dimas [21]
L'Hopital rule only applies to indeterminate cases of 0/0 or ∞/∞ or 0*0 or ∞ * ∞.

and you'd need to make the expression a rational, where the numerator and denominator gives you 0/0 or ∞/∞, then you apply L'Hopital.

the only candidate there is 

\bf \lim\limits_{x\to \infty}\cfrac{2x^2-1}{3x+1}\implies \lim\limits_{x\to \infty}\cfrac{2(\infty)^2-1}{3(\infty)+1}\implies \cfrac{\infty}{\infty}
\\\\\\
\textit{so we can use L'Hopital by instead using the derivatives}
\\\\\\
\lim\limits_{x\to \infty}\cfrac{2x^2-1}{3x+1}\stackrel{LH}{\implies }\lim\limits_{x\to \infty}\cfrac{4x}{3}\implies \cfrac{4(\infty)}{3}\implies \infty
8 0
3 years ago
Find the x-coordinate of the point on the graph of y=x^2 where the tangent line is parallel to the secant line that cuts the cur
jek_recluse [69]
First find the secant line. The slope of the secant line through (-1,1) (when x=-1) and (2,4) (when x=2) is the average rate of change of y=x^2 over the interval [-1,2]:

\text{slope}_{\text{secant}}=\dfrac{2^2-(-1)^2}{2-(-1)}=\dfrac33=1

The tangent line to y=x^2 will have a slope determined by the derivative:

y=x^2\implies y'=2x

Both the secant and tangent will have the same slope when 2x=1, or when x=\dfrac12.
4 0
2 years ago
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