Point slope form is y-y1= m(x-x1) where m is slope and y1 and x1 are the x and y of the coordinate given.
y-1= 2(x-(-2))
y-1= 2(x+2)
Final answer: y-1= 2(x+2)
m∠FDE = 52°
Solution:
Given data:
DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠ABF + m∠CBF = 180°
116° + m∠CBF = 180°
m∠CBF = 64°
If CD || BE, then CD || BF.
Hence CD || BE and BE || FD.
Therefore BFCD is a parallelogam.
<em>In parallelogram, Adjacent angles form a linear pair.</em>
m∠CBF + m∠BFD = 180°
64° + m∠BFD = 180°
m∠BFD = 116°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠BFD + m∠DFE = 180°
116° + m∠DFE = 180°
m∠DFE = 64°
we know that DE ≅ DF.
<em>In triangle, angles opposite to equal sides are equal.</em>
m∠DFE = m∠DEF
m∠DEF = 64°
<em>sum of all the angles of a triangle = 180°</em>
m∠DFE + m∠DEF + m∠FDE = 180°
64° + 64° + m∠FDE = 180°
m∠FDE = 52°
Answer:
Step-by-step explanation:
We can solve this in either of two ways. I'll do both.
<u>Mathematically</u>
3x + 2y = 8
5x + 2y = 12
Rewrite either equation to isolate y. I'll use
3x + 2y = 8
2y = 8 - 3x
y = (8-3x)/2
Now use this value of y in the other equation:
5x + 2y = 12
5x + 2((8-3x)/2) = 12
5x + (8 - 3x) = 12
2x = 4
x = 2
Use x=2 to find y:
y = (8-3x)/2
y = (8-3*(2))/2
y = (8-6)/2
y = 1
The point is (2,1)
<u>Graphically</u>
Graph the two equations and find the point they intersect. See attachment.
We obtain the same answer: (2,1)
Answer:
0.046231
just use a calculator my dude
