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3 years ago

PLEASE HELP and Show your work please!!

Mathematics

1 answer:

bazaltina [42]3 years ago

8 0

9514 1404 393

Answer:

2) 3 pages per hour

3) 4/29 km per minute

Step-by-step explanation:

Division by a fraction is the same as multiplication by the inverse of that fraction.

$\dfrac{\ \dfrac{9}{4}\ }{\dfrac{3}{4}}=\dfrac{9}{4}\times\dfrac{4}{3}=\dfrac{36}{12}=\boxed{3\text{ pages per hour}}$

$\dfrac{2\text{ km}}{\dfrac{29}{2}\text{ min}}=2\times\dfrac{2}{29}\text{ km/min}=\boxed{\dfrac{4}{29}\text{ km/min}}$

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The weights of bags of grasecks chocolate candies are normally distributed with a mean of 4.3 ounces and a standard deviation of

skelet666 [1.2K]

Answer: 0.2743

Step-by-step explanation:

Let X be a random variable that represents the weight of bags of grasecks chocolate candoes.

X that follows normal distribution with, Mean = 4.3 ounces, Standard devaition = 0.05 ounces

The probability that a bag of these chocolate candies weighs less than 4.27 ounces : $P(X$

$=P(z$

Hence, the required probability = 0.2743

7 0

3 years ago

A company makes a profit of $50 per software program and $35 per video game. the company can produce at most 200 software progra

Neko [114]

Let x = software program
Let y = video game

x < 200 ; y < 300

x + y < 425

50x ; 35y

x = 200 ; y = 225
50(200) + 35(225) = 10,000 + 7,875 = 17,875

x = 125 ; y = 300
50(125) + 35(300) = 6,250 + 10,500 = 16,750

x = 175 ; y = 250
50(175) + 35(250) = 8,750 + 8,750 = 17,500

It is more profitable to maximize production of software program when working within the limits provided.

4 0

3 years ago

Read 2 more answers

The carnival is in town for 21 days. How many weeks is the carnival in town?(There are 7 days in 1 week.) Write and equation,and

Elza [17]

Answer:

egn= 7x=y

where x= weeks no.

y= days

atq...x= 3

4 0

3 years ago

Order 10,16,18,24,14,17,26,15,14,

Anettt [7]

Order : 6 9 9 10 12 15 15 17 18

Mean: 12.33

Median: 12

mode: 9 and 15

range: 12

6 0

3 years ago

The length of time required for the periodic maintenance of an automobile or another machine usually has a mound-shaped probabil

maks197457 [2]

Solution :

Mean time for an automobile to run a 5000 mile check and service = 1.4 hours

Standard deviation = 0.7 hours

Maximum average service time = 1.6 hours for one automobile

The z - score for 1.6 hours = $\frac{1.6-1.4}{0.7 / \sqrt{50}}$

= 2.02

Now checking a normal curve table the percentage of z score over 2.02 is 0.0217

Therefore the overtime that will have to be worked on only 0.217 or 2.017% of all days.

8 0

3 years ago