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Rina8888 [55]
3 years ago
12

6. (09.02 MC)

Mathematics
1 answer:
Llana [10]3 years ago
5 0

Answer:

Hello,

Step-by-step explanation:

v_x(t)=ln(t-2)\ \Longrightarrow\ a_x(t)=\dfrac{1}{t-2} \\\\v_y(t)=e^{2t-t^2}\ \Longrightarrow\ a_y(t)=e^{2t-t^2}*(2-2t)\\\\t=3\ i\ suppose\ \\\\a_x(3)=\dfrac{1}{3-2}=1\\\\a_y(t)=e^{6-9}*(2-6)=-\dfrac{4}{e^3}

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