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2 years ago

Please help me with this

Mathematics

1 answer:

3241004551 [841]2 years ago

3 0

Answer:

Will

Step-by-step explanation:

Katie runs 8 feet per second

Stephanie runs 10.88 feet per second

Liz runs 12.9 feet per second

Will runs 13.45 feet per second

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Janet plans to save $22.50 each week until she has enough to buy a $180 bicycle. After how many weeks will she have enough money

Darya [45]

Answer:

Step-by-step explanation:

8weeeks bc 22.50*8=180

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2 years ago

I found a picture showing how pi = 4. What is wrong with this picture?

Kazeer [188]

Answer:

Step-by-step explanation:

its not an acshual circle and the answer would be a decimal

3 0

3 years ago

Read 2 more answers

Someone please help me with this

mina [271]

Answer:

The answer is 42.

Step-by-step explanation:

5n - 13 = 42

5n = 42 + 13

5n = 55

n = 11

explanation about the solution = The angles formed by the segments measuring 42 and 5n - 13 are equal in measure which means the segments are as well.

5 0

3 years ago

A farmer has 500 acres to plant acres of corn, x, and acres of cotton, y. Corn costs $215 per acre to produce, and cotton costs

tatyana61 [14]

Answer:

The system that represent the scenario is

$x+y\leq500$

$215x+615y\leq 187,500$

The solution in the attached figure

Step-by-step explanation:

Let

x-----> the acres of corn

y----> the acres of cotton

we know that

$x+y\leq500$ ------> inequality A

$215x+615y\leq 187,500$ -----> inequality B

using a graphing tool

the solution is the shaded area in the attached figure

8 0

3 years ago

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One day, eleven babies are born at a hospital. Assuming each baby has an equal chance of being a boy or girl, what is the probab

Andrews [41]

You only need to consider the situations where 10 or 11 of the babies are girls, then subtract those probabilities from 1. This will give probability that any other number up to 9 of the babies are girls.

Use binomial theorem.
$P(x=k) = (nCk) p^k (1-p)^{n-k}$

n = 11
k = 10,11
p = 1/2

$P(x=10) = 11 (\frac{1}{2})^{11} = \frac{11}{2048} \\ \\ P(x=11) = 1(\frac{1}{2})^{11} = \frac{1}{2048} \\ \\ P(x \leq 9) = 1 - \frac{11}{2048} - \frac{1}{2048} \\ \\ P(x \leq 9)=\frac{2036}{2048} = \frac{509}{512}$

4 0

3 years ago