Answer:
x-35>15
x>15+35
x>50
Answer:
a) 151lb.
b) 6.25 lb
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean
and standard deviation
, a large sample size can be approximated to a normal distribution with mean
and standard deviation
.
In this problem, we have that:

So
a) The expected value of the sample mean of the weights is 151 lb.
(b) What is the standard deviation of the sampling distribution of the sample mean weight?
This is 
Answer:
-9x + 13
Step-by-step explanation:
9 -3x +(-6x) +4
you will add -3x+(-6x), then add 9+4
-3x+(-6x) = -9x (a negative pus and negative = a negative
9 +4 = 13
-9x + 13
Answer:
C. 72 sorry if its wrong
Step-by-step explanation:
trapezoid formula : A= 1/2h(B+b)
plug in:
A= 1/2×6(10+14)
A= 3(24)
A= 72
Answer:
250 miles
Step-by-step explanation:
So we know that the time (t) equals 5 hours and that the rate (r) equals 50 mph. So knowing that, we can use the formula t*r=distance. We plug in the numbers and we get 250 miles.
Another way to think about this is, since we go 5 hours and 50 miles per hour, every hour we go 50 miles and we do that for 5 hours, so we go 50, 100, 150, 200, 250.