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djverab [1.8K]
2 years ago
6

The length of a rectangle is 5ft longer than twice the width if the perimeter is 58 ft find the length and width of the rectangl

e
Mathematics
2 answers:
Travka [436]2 years ago
3 0
----------------------------------
Define x :
----------------------------------
Let the width be x.
Width = x
Length = 2x + 5                // Length is 5ft longer than twice the width

----------------------------------
Formula for Perimeter :
----------------------------------
Perimeter = 2 (Length + Width)

----------------------------------
Find Width :
----------------------------------
58 = 2 ( 2x + 5 + x)         // Substitute Length and Width into formula
58 = 2 (3x + 5)                // Combine like terms
58 = 6x + 10                    // Apply distributive property
48 = 6x                            // Take away 10 from both sides
6x = 48                            // Switch sides. Make x the subject
x = 8                                // Divide by 6 on both sides

----------------------------------
Find Length and Width :
----------------------------------
Width = x = 8 ft
Length = 2x + 5 = 2(8) + 5 = 21 ft

--------------------------------------------------------------------
Answer: The length is 21 ft and the width is 8 ft.
--------------------------------------------------------------------

slava [35]2 years ago
3 0
Length= 5+2x
Width = x

Perimeter = 2(l+w)=58
= 2(5+2x+x)=58
= 2(5+3x)=58
= 10+6x =58
= 6x= 48
X= 8
Width=8
Length= 21
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Similarly, the standard deviation of the binomial distribution is given by the formula;

            Standard deviation, \sigma  =  \sqrt{n \times p \times (1-p)}

                                                  =  \sqrt{36 \times 0.75 \times (1-0.75)}

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