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Tju [1.3M]
2 years ago
6

Good science requires that you record your observations accurately. TrueFalse

Mathematics
1 answer:
enyata [817]2 years ago
6 0

Answer:

True.

Step-by-step explanation:

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James calculated the height of a cylinder that has a volume of 324 pi cubic inches and a radius of 12 in his work is shown below
wel

Answer:

13.5cm

Step-by-step explanation:

V=Bn

Step 1: 3245 - 12h

Step 2: 324 = 24 sh

324 24

Step 3: 245 245

Step 4: h-13.5

inches

What is the first error that James made when calculating the height of the cylinder?

In step 1, he substituted into the volume formula incorrectly.

In step 2, he calculated 122 incorrectly. It should be 144 rather than 24.

In step 4, the should have canceled, making the correct answer 13.5 cm.

James calculated the height of the cylinder correctly

7 0
3 years ago
Read 2 more answers
Help me with this please
drek231 [11]
The answer is only C and D
6 0
3 years ago
Can someone help me with this, please & thanks. :)
Rasek [7]
Multiply bath sides by (-13)


Step 1:(-13).a/(-13) <= -16(-13) ===> . Mistake since she the < sign into >

Step 2: a<=208  is the right answer


Step 3: The line should go from 208 to the left & not to the right
7 0
3 years ago
Simplify (1 - sin x)(1 + sin x).<br> 0 1<br> O cos^2 x<br> O sin^2 x<br> O tan^2 x
V125BC [204]
This would be cos^2x, because when you foil out the equation you get 1-sin^2(x).

1-sin^2(x)=cos^2(x)
5 0
3 years ago
Use cylindrical coordinates. evaluate x dv e , where e is enclosed by the planes z = 0 and z = x + y + 10 and by the cylinders x
gizmo_the_mogwai [7]
In cylindrical coordinates,

\begin{cases}x(X,Y,Z)=X\cos Y\\y(X,Y,Z)=X\sin Y\\z(X,Y,Z)=Z\end{cases}\implies\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=X\,\mathrm dX\,\mathrm dY\,\mathrm dZ

Then the integral is

\displaystyle\iiint_Ex\,\mathrm dV=\int_{Y=0}^{Y=2\pi}\int_{X=4}^{X=6}\int_{Z=0}^{Z=X\cos Y+X\sin Y+10}X\cos Y\times X\,\mathrm dZ\,\mathrm dX\,\mathrm dY
=\displaystyle\int_{Y=0}^{Y=2\pi}\int_{X=4}^{X=6}(10X^2\cos Y+X^3\cos^2Y+X^3\cos Y\sin Y)\,\mathrm dX\,\mathrm dY
=\displaystyle\int_{Y=0}^{Y=2\pi}\left(\dfrac{1520}3\cos Y+260\cos^2Y+260\cos Y\sin Y\right)\,\mathrm dY=260\pi
5 0
3 years ago
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