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3 years ago

Can anyone please help me to find the area of this please

Mathematics

1 answer:

valentinak56 [21]3 years ago

5 0

9514 1404 393

Answer:

√35 +3√7 -6 . . . square units

Step-by-step explanation:

The area can be figured a number of ways. The figure can be divided into parts, and the areas of those parts added.

Or, the area of the enclosing rectangle can be found, and the rectangle at upper right that is not shaded can be subtracted from that. We choose the latter.

The overall width is the sum of the given partial widths:

width = (√7 -2) + (2) = √7

Then the area of the bounding rectangle is ...

A = LW = (√5 +3)(√7) = √35 +3√7

The area of the upper right empty-space is ...

A = LW = (3)(2) = 6

Then The area of the shaded figure is ...

√35 +3√7 -6

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3 years ago

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5 0

2 years ago

A rectangle has an area of 4 square centimeters. A second rectangle is 3 times as long and 3 times as wide as the first rectangl

vekshin1

Answer:

The area of the second rectangle will be 36 square centimetres

Step-by-step explanation:

Given:

Area of the first rectangle = 4 square centimetres

A second rectangle is 3 times as long and 3 times as wide as the first rectangle

To Find:

Area of the second rectangle = ?

Solution:

We know that area of the rectangle is Length X breadth

Length X width = 4

In this case the are 2 possibilities

Case 1:

Length = 2 cm

Width = 2 cm

2 X 2 = 4

Now According to the question

Length is 3 times = 2 X 3 = 6cm

width is also 3 times = 2 X 3 = 6 cm

Now the area of the second rectangle will be

6 X 6 = 36 square centimetres

Case 2:

Length = 4 cm

Width = 1 cm

4 X 1 = 4

Now According to the question

Length is 3 times = 4 X 3 = 12 cm

width is also 3 times = 1 X 3 =3 cm

Now the area of the second rectangle will be

12 X 3 = 36 square centimetres

5 0

3 years ago

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Function for given situation is : $V(t)=3000(0.70)^t$

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