Answer:
Impossible
Step-by-step explanation:
In 5x^2-4x+3=0, standard form, substitute these values in the quadratic formula:
a = 5; b = -4; c = 3
The quadratic formula is ![x = \frac{ -b ± \sqrt{b^{2} - 4ac}}{2a}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B%20-b%20%C2%B1%20%5Csqrt%7Bb%5E%7B2%7D%20-%204ac%7D%7D%7B2a%7D)
(ignore the weird capital A)
Substitute a b and c:
![x = \frac{-(-4) ± \sqrt{(-4)^{2} - 4(5)(3)}}{2(5)}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B-%28-4%29%20%C2%B1%20%5Csqrt%7B%28-4%29%5E%7B2%7D%20-%204%285%29%283%29%7D%7D%7B2%285%29%7D)
Simplify:
![x = \frac{4) ± \sqrt{16 - 60}}{10}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B4%29%20%C2%B1%20%5Csqrt%7B16%20-%2060%7D%7D%7B10%7D)
Because
is the square root of a negative number, the answer would be imaginary.
Therefore, there are not solutions to this equation.
A solution is the same as the roots or zeroes, where the graph would cross the x-axis when graphed.
The graph never meets the x-axis. It looks like this:
This is the answer -0.25,0.12,6/8
Answer:
b=3/4
Step-by-step explanation:
((3/4)x)/2=9/32
Answer:
Hi! The answer to your question is ![-1/12](https://tex.z-dn.net/?f=-1%2F12)
Step-by-step explanation:
☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆
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Answer:
Increasing in x < 7 and decreasing in x > 7.
Step-by-step explanation:
g(x) = 1 - ![(x-7)^{2}](https://tex.z-dn.net/?f=%28x-7%29%5E%7B2%7D)
![\frac{dg(x)}{dx} = -2(x - 7)](https://tex.z-dn.net/?f=%5Cfrac%7Bdg%28x%29%7D%7Bdx%7D%20%3D%20-2%28x%20-%207%29)
<u>If a function is increasing in a interval, its first derivative is positive and if a function is decreasing in an intreval, its first derivative is negative.</u>
Using this concept here,
Substitute x > 7,
the first derivative is negative.Hence it is decreasing in this interval.
Substitute x < 7,
The first derivative is positive.Hence it is increasing in this interval.
Hence the answer is increasing in x < 7 and decreasing in x > 7.