Answer:
1. 5/6 ≥ 2/3
2. 1/5 ≤ 2/8
3. 9/10 ≥ 6/8
4. I can't see it's out of the pic
5. 7/8 ≥ 5/10
6. 2/5 ≥ 2/6
7. 1/3 ≤ 3/8
8. I can't see it's out of the pic.
9. 8/10 ≥ 3/4
10. 3/8 ≤ 11/12
11. 2/3 ≤ 10/12
12. Can't see :(
13. 3/8 ≤ 7/8
14. 2/4 = 4/8
15. 6/8 ≥ 8/12
16. Can't see
Step-by-step explanation: All you have to do is divide the numerator by the denominator to make it into a decimal. For instance....
5/6 = approximately 0.83
I hope this helps you! It took forever....
You can solve this by using the system of equations.
Jan - 4.95 = 2H + 3C
Wayne - 5.45 = 3H + 2C
Use elimination.
-3(2H + 3C = 4.95)
2(3H + 2C = 5.45)
Solve. And you'll get:
-6H + (-9C) = -14.85
6H + 4C = 10.9
Cross out -6H and 6H because they cancel out. And you're left with:
-9C = -14.85
4C = 10.9
Add -9C with 4C, and -14.85 with 10.9.
-5C = -3.95
Divide each side with -5.
C = $0.79
Now to figure out what H is, just substitute the C in one of the equations with 0.79.
5.45 = 3H + 2(0.79)
5.45 = 3H + 1.58
-1.58 -1.58
3.87 = 3H
3.87/3 = 3/3(H)
1.29 = H
Finished!
Haha, you first start off with adding 3 to both sides, cancelling the -3, and adding it to 9. you end up with 5x=12, in which you divide both sides by 5. you get 2 and 2/5 or 12/5! hope that helps :)
First, we are going to find the vertex of our quadratic. Remember that to find the vertex

of a quadratic equation of the form

, we use the vertex formula

, and then, we evaluate our equation at

to find

.
We now from our quadratic that

and

, so lets use our formula:




Now we can evaluate our quadratic at 8 to find

:




So the vertex of our function is (8,-72)
Next, we are going to use the vertex to rewrite our quadratic equation:



The x-coordinate of the minimum will be the x-coordinate of the vertex; in other words: 8.
We can conclude that:
The rewritten equation is

The x-coordinate of the minimum is 8
Answer:
Maby b
Step-by-step explanation:
sorry if wrong