your answer is
W<5.
the graphic will be like my drawing I hope you understand it because it is difficult to draw here
Answer:
B
Step-by-step explanation:
Using the determinant to determine the type of zeros
Given
f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct zeros
• If b² - 4ac = 0 then 2 real and equal zeros
• If b² - 4ac < 0 then 2 complex zeros
Given
f(x) = (x - 1)² + 1 ← expand factor and simplify
= x² - 2x + 1 + 1
= x² - 2x + 2 ← in standard form
with a = 1, b = - 2, c = 2, then
b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4
Since b² - 4ac < 0 then the zeros are complex
Thus P(x) has no real zeros
Hey there! :)
Your answer is: Between 11 and 12
11² = 11 × 11 = 121
12² = 12 × 12 = 144
129 is between 121 and 144
Hope this helps :)
Answer:
Step-by-step explanation:
remember: tan(theta) = opposite/adjacent
Answer:
x = 28
Step-by-step explanation:
