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babunello [35]
3 years ago
11

What is 40-32divited by8=5x-2

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
4 0
4.


40-32 is equal to 8.

8=5x-2 is equal to 2.


8/2 is 4.
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Can someone help me with this two questions pls!!! I don't know how I can solve pls!
aivan3 [116]
20)

\bf ~~~~~~~~~~~~\textit{negative exponents}\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\\\
\textit{also recall that }a^{\frac{ n}{ m}} \implies  \sqrt[ m]{a^ n} 
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}
\\\\
-------------------------------

\bf \cfrac{(-54)^2}{\sqrt[3]{(-54)^5}}\implies \cfrac{(-54)^2}{(-54)^{\frac{5}{3}}}\implies (-54)^2(-54)^{-\frac{5}{3}}\implies (-54)^{2-\frac{5}{3}}
\\\\\\
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\\\\\\
\begin{cases}
54=2\cdot 3\cdot 3\cdot 3\\
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22)

\bf -5\sqrt[3]{2x+3}=15\impliedby \textit{we first raise both sides by }^3
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\\\\\\
(-125)(2x+3)=3375\implies 2x+3=\cfrac{3375}{-125}\implies 2x+3=-27
\\\\\\
2x=-30\implies x=-\cfrac{30}{2}\implies x=-15
4 0
4 years ago
Read 2 more answers
Harry owes the bank money. To repay his debt, he paid \$150$150dollar sign, 150 back to the bank each month. After 101010 months
Sonja [21]


$8,400
Explanation:
Amount repaid each month = $150
Number of Periods for which amount was paid = 10 months
Amount left after 10 months payment = $6900
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Total debt amount:
(Total Amount left + total amount paid )
$(6900 + 1500)
7 0
3 years ago
I only need help with A.
Vlada [557]
15 x 20 and 10 x 30 hope this works
6 0
3 years ago
How to multiply to the n<br>earest ten
Tcecarenko [31]
I'm not sure what you mean by this, but if you mean rounding, I got an answer.

Say you're rounding 24 to 30.
24 is closer to 20 than 30.

But if you were rounding 25 to 30, 25 would be closer to 30, not 20.
I guess it's kind of confusing.
4 0
3 years ago
Which of the following is true regarding the solution to the logarithmic equation below? log Subscript 2 Baseline (x + 11) = 4.
meriva

Answer:

Option C.

Step-by-step explanation:

The given logarithmic equation is

\log_2(x+11)=4

It can be written as

(x+11)=2^4     [\because log_ax=y\Leftrightarrow x=a^y]

x+11=16

x=5

Now, to check whether x=5 is a true solution or not. Substitute x=5 in the LHS of given equation.

LHS=\log_2(5+11)

LHS=\log_2(16)

LHS=\log_22^4

LHS=4     [\because log_aa^x=x]

LHS=RHS

Hence, x=5 is a true solution because \log_2(16)=4.

Therefore, the correct option is C.

5 0
3 years ago
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