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2 years ago

On which table is y not a function of x?

Mathematics

1 answer:

REY [17]2 years ago

4 0

Answer:

look here bozo

Step-by-step explanation:

the answer is d

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Terry bought 5 pounds of strawberries for $15. Which equation can be used to find the cost per pound of strawberries,x?

Brums [2.3K]

Answer:

5x=15

Step-by-step explanation:

5pounds times the price per pound (x) equals $15

7 0

2 years ago

Which of the following functions is graphed below?

erastovalidia [21]

Could you please attach the graph itself because the question is not proper

3 0

3 years ago

PLEASE HELP ME ASAP!!!!!!

melamori03 [73]

Answer:

Step-by-step explanation:

3 0

2 years ago

4.58+y=2.5<br><br> y= ??????

zepelin [54]

Answer:

-2.08

Step-by-step explanation:

If you just switch the problem, to make it 4.58-2.5, you get negative 2.5

6 0

2 years ago

Read 2 more answers

A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a

sineoko [7]

ANSWER

The scale factor is
$2.5$

EXPLANATION

The given triangle has vertices,

$A(0,0),B(0,4),\:and\:C(6, 0)$ .

The vertices of the image triangle is,

$A'(0,0),B'(0,10),\:and\:C'(15, 0)$ .

The scale factor is given by

$k = \frac{image \: length}{object \: length}$

So we can use any of the corresponding sides to determine the scale factor,

$k = \frac{|A'B'|}{ |AB|}$

$k = \frac{ |10 - 0| }{ |4 - 0|}$

$k = \frac{ |10| }{ |4 |} = \frac{10}{4} = 2.5$

Or

$k = \frac{|A'C'|}{ |AC|}$

$k = \frac{ |15 - 0| }{ |6 - 0|}$

$k = \frac{ |15| }{ |6|} = \frac{15}{6} = 2.5$

Or

$k=\frac{|B'C'|}{|BC|}$

$k = \frac{\sqrt{(15 - 0)^2+(0-10)^2 }}{\sqrt{(6 - 0)^2+(0-4)^2}}$

$k = \frac{ 5\sqrt{13}}{2\sqrt{13}} = \frac{5}{2} = 2.5$

The correct answer is C

3 0

2 years ago