Answer:
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
Step-by-step explanation:
Given that a poll was taken this year asking college students if they considered themselves overweight. A similar poll was taken 5 years ago.
Let five years ago be group I X and as of now be group II Y

(Two tailed test at 5% level of significance)
Group I Group II combined p
n 270 300 570
favor 120 140 260
p 0.4444 0.4667 0.4561
Std error for differene = 
p difference = -0.0223
Z statistic = p diff/std error = -1.066
p value =0.2864
Since p value >0.05, we accept null hypothesis.
At 5% significance level, it is statistically evident that there is nodifference in the proportion of college students who consider themselves overweight between the two poll
Answer:
c = 1.5 d
Step-by-step explanation:
cost of 4 small drinks = $6
cost of 1 small drink = $
= $1.5
cost of d small drinks = 1.5 d = c
∴ c = 1.5 d
3 1/2 pound = 7/2 pounds.
We know that the dog eats 7/2 (3.5) pounds every 21 days since there are 7 days in a week and Mr.Z only buys dog food every 3 weeks.
Set up a proportion. <u>3.5 lb</u> = <u> x </u><u>
</u> 21 days 365 days
<u>
</u>Cross multiply and divide. 3.5 lb x 365 days = 1277.5 / 21 days = 60.83 lb
<u>
</u>
513 * 40 + 513 * 6= 2052 + 3078 = 5130
35 would be positive while 40 would be negative