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jenyasd209 [6]
3 years ago
12

Write an equation of the line that passes through the given points: (9/2,1), (-7/2,7) please show step by step how to do this. T

he answer should be: y=-3/4x+35/8.
Mathematics
1 answer:
Viktor [21]3 years ago
6 0

Explanation:

The easiest way to do this is to make use of the 2-point form of the equation for a line. For points (x₁, y₁) and (x₂, y₂), the equation is ...

  y=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)+y_1

Filling in your given points, the equation becomes ...

  y=\dfrac{7-1}{\frac{-7}{2}-\frac{9}{2}}(x-\frac{9}{2})+1

After you fill in the values, it is a matter of simplifying the resulting equation.

y=\dfrac{6}{\frac{-16}{2}}(x-\frac{9}{2})+1=\dfrac{-12}{16}(x-\frac{9}{2})+1=-\dfrac{3}{4}x+\left(\dfrac{-3}{4}\cdot\dfrac{-9}{2}\right)+1\\\\y=-\dfrac{3}{4}x+\dfrac{27+8}{8}\\\\y=-\dfrac{3}{4}x+\dfrac{35}{8}

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6 0
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Find 0.1 more than 5.023.<br> A) 5.024 <br> B) 5.033 <br> C) 5.123 <br> D) 5.134
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C. the number goes up by one tenth. changing the 0 in the tenth place to a one.

8 0
3 years ago
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What value does ​f(x,y) = (x + 2y)/(x -2y) approach as​ (x,y) approaches​ (0,0) along the​ x-axis?
WARRIOR [948]

Answer:

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Step-by-step explanation:

Given the function

​f(x,y) = (x + 2y)/(x -2y)

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y = mx

then

lim (x,y) → (0, 0)  f(x,y) = lim (x,mx) → (0, 0)  f(x, mx)

⇒  lim (x → 0) (x + 2mx)/(x -2mx) = lim (x → 0) x(1+2m)/(x*(1-2m)) = (1+2m)/(1-2m)

If

y = x²

then

lim (x,y) → (0, 0)  f(x,y) = lim (x → 0)  f(x)

⇒  lim (x → 0) (x + 2x²)/(x -2x²) = (1 + 4(0))/(1 - 4(0)) = 1

If

y = x³

then

lim (x,y) → (0, 0)  f(x,y) = lim (x → 0)  f(x)

⇒  lim (x → 0) (x + 2x³)/(x -2x³) = (1 + 6(0)²)/(1 - 6(0)²) = 1

We applied L'Hopital's rule to solve the limits.

Then, we can say that ​f(x,y) has no limit since the limits obtained are different.

4 0
3 years ago
Pls help and explain
grin007 [14]

Answer:

B

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First distribute the 2x to get:

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Then combine

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4x² - 25

4 0
2 years ago
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