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3 years ago

This question is from set can anyone answer me !

Mathematics

1 answer:

Virty [35]3 years ago

3 0

Answer:

n (aub)= n (a)+ n(b)

n (anb) = n (a)-n (b)

only a= n(a)+n(b) -(aub)

n only b= n (a)+n (b)-n (anb)

now solve your self because this formula help to solve

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Find the circumference of a circle whose area is /. A. B. C. D.

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What is the equation of the circle whose diameter has endpoints (8,-2) and (-2,6)?

klemol [59]

Answer:

$(x-3)^{2} +(y-2)^{2}=41$

Step-by-step explanation:

step 1

Find the diameter of the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$A(8,-2)\\E(-2,6)$

substitute the values

$d=\sqrt{(6+2)^{2}+(-2-8)^{2}}$

$d=\sqrt{(8)^{2}+(-10)^{2}}$

$d=\sqrt{164}\ units$

$d=2\sqrt{41}\ units$

step 2

Find the center of the circle

The center is the midpoint of the diameter

The center is equal to

$C=(\frac{8-2}{2},\frac{-2+6}{2})$

$C=(3,2)$

step 3

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The equation of the circle in center radius form is equal to

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we have

(h,k)=(3,2)

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substitute

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4 years ago

Plzz solve this easy calculus :')

Digiron [165]

Answer:

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Step-by-step explanation:

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