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katen-ka-za [31]
3 years ago
9

The total cost of 2 bracelets and 3 necklaces is $15.50. The total cost of 4 bracelets and 1 necklace is $13.50. Let b represent

the cost of each bracelet and n represent the cost of each necklace. This situation can be represented by the following system of equations.
{2b+3n=15.504b+n=13.50

What is the cost of one bracelet?

A
$2.50

B
$7.75

C
$5.00

D
$3.50
Mathematics
1 answer:
Kaylis [27]3 years ago
4 0

Answer:

A

$2.50

Step-by-step explanation:

b = cost of bracelet

n = cost of necklace

2b+3n = 15.50

4b+1n = 13.50

Multiply the first equation by -2

-4b -6n = -31

4b +n = 13.50

---------------------------

-5n = -17.50

Divide each side by -5

-5n/-5 = -17.5/-5

n = 3.50

Now we can find b

4b+n = 13.50

4b+3.50 = 13.50

4b+3.50-3.50 = 13.50 -3.50

4b = 10

Divide by 4

4b/4 = 10/4

b = 2.50

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Distance to travel = 20 m.
Let us determine the time, t, that each participant took to complete 20 m.

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What’s the value of <br> tan (3arc cos 3/4)
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