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3 years ago

How do i find the area and perimeter?

Mathematics

1 answer:

Flura [38]3 years ago

7 0

Calculating the area and the perimeter The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides. x is in this case the length of the rectangle while y is the width of the rectangle.

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LOL ANOTHER MATH QUESTION ASAP!!!

Inessa05 [86]

Your answer is the first one q

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3 years ago

Read 2 more answers

Data from the Centers for Disease Control and Prevention indicate that weights of American adults in 2005 had a mean of 167 poun

sesenic [268]

Answer:

92.65% probability that the total weight in a random sample of 47 American adults exceeds 7500 pounds in 2005.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums the theorem can also be used, with mean $n*\mu$ and standard deviation $s = \sqrt{n}*\sigma$

In this problem, we have that:

$n = 47, \mu = 47*167 = 7849, s = \sqrt{47}*35 = 240$

Use this information to estimate the probability that the total weight in a random sample of 47 American adults exceeds 7500 pounds in 2005.

This is 1 subtracted by the pvalue of Z when X = 7500. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{7500 - 7849}{240}$

$Z = -1.45$

$Z = -1.45$ has a pvalue of 0.0735

1 - 0.0735 = 0.9265

92.65% probability that the total weight in a random sample of 47 American adults exceeds 7500 pounds in 2005.

5 0

3 years ago

A set of children’s blocks contains three shapes: long, flats, and cubes. There are three times as many longs as cubes and 30 fe

kati45 [8]

Answer:

<u>There are 270 longs</u>

Step-by-step explanation:

<u>Equations</u>

We must write the problem into a mathematical model that allows us to apply the properties of basic algebra and solve for the variable which must be adequately set up.

We have three unknowns: the number of long blocks, flats blocks, and cubes. The conditions are given:

There are three times as many longs as cubes
There are 30 fewer flats than longs.
There are 600 blocks in all

For the equation to be easier solved, let's set the variable as the number of cubes:

x = number of cubes

Considering the first condition, we have

3x = number of longs

3x-30 = number of flats

And finally:

$x + 3x+3x-30=600$

Joining like terms:

$7x=630$

Solving for x

$\displaystyle x=\frac{630}{7}=90$

Therefore, there are 3x = 3*(90) = 270 longs

Answer: there are 270 longs

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3 years ago

Two angles are complementary. The larger

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

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3 years ago

a. For each of the Five Platonic Solids, count the number V of vertices, the number F of faces, and the number E of edges. Check

natita [175]

Answer:

1. The tetrahedron has 4 vertices, 6 edges and 4 faces. Then V-E+F=4-6+4=2

2. The cube has 8 vertices, 12 edges and 6 faces. Then V-E+F=8-12+6=2

3. The octahedron has 6 vertices, 12 edges and 8 faces. Then V-E+F=6-12+8=2

4. The icosahedron has 12 vertices, 30 edges and 20 faces. Then V-E+F=12-30+20=2

5. The dodecahedron has 20 vertices, 30 edges and 12 faces. Then V-E+F=20-30+12=2.

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3 years ago