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aleksandr82 [10.1K]
3 years ago
11

Sandra wants to evaluate 2 cot Her work is shown below. What did she do wrong?

Mathematics
1 answer:
Rashid [163]3 years ago
8 0

Answer: The first option.


Step-by-step explanation:

1. You need to remember that:

- An even function is a function with the following property:

f(-x)=f(x)

- An odd function  is a function with the following property:

f(-x)=-f(x)

2. By definition, the contangent is an odd function, therefore you have that:

cot(-θ)=-cot(θ)

Then:

2cot(-\frac{9\pi}{2})\neq2cot(\frac{9\pi}{2})

3. So, you can coclude that the first step is wrong. Therefore, the answer is the first option.



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Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178
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Answer:

2x+178\geq 2000

Step-by-step explanation:

Let, the number of cans collected by Shane = x.

So, the number of cans collected by Abha = x + 178.

Since, at least 2000 cans are required to be collected.

Thus, we have the inequality,

Number of cans by Shane + Number of cans by Abha ≥ 2000.

i.e. x+(x+178)\geq 2000

i.e. 2x+178\geq 2000

Thus, the required inequality is 2x+178\geq 2000.

4 0
3 years ago
Bella has $540 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax.
ASHA 777 [7]

Answer:

Bella spent 407.16 and has 132.84 left. she could buy like 2 outfits

Step-by-step explanation:

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3 years ago
Help please! I just need to know how to do this step by step...
Alex787 [66]

-8 - 5n = 64 + 3n

    +5n          +5n           add 5n to both sides, 5n's cancel out on the left.

______________

-8 = 64 + 8n

-64 -64                          subtract 64 on both sides, 64's cancel out on the right.

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-72 = 8n

___  ___                       divide 8 on both sides, 8's cancel out from the right.

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What is the solution to the equation? <br> x – 19 = 1
Romashka-Z-Leto [24]
+ 19 on both sides, -19 becomes 0, 1 becomes 20 x=20
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3 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
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