Ask question

Ask question

All categories

3 years ago

11

A mountain climber ascends a mountain to its peak. The peak is 14,090 ft above sea level. The climber then descends 490 ft to me

et a fellow climber. Find the climber’s elevation above sea level after meeting the other climber.

2 answers:

Aleks04 [339]3 years ago

8 0

The value of asked for is obtained by subtracting the distance traveled downward by the climber from the peak elevation. This is shown below,
d = 14,090 ft - 490 ft
The value is equal to 13600 ft. Thus, the climber is 13,600 ft from the ground.

Usimov [2.4K]3 years ago

4 0

14090 ft - 490 ft = 13600 ft
that would be the climber's current elevation above sea level

You might be interested in

an underground mine elevator reaches a total depth of 99 meters. it descends 17% of the total distance every minute. how many me

malfutka [58]

17% of 99 is 16.83. Since that's only the distance it goes in one minute we have to multiply that by 3. 16.83 × 3 = 50.49. Since the elevator is moving down then it will be negative. The answer will be -50.49 meters.

4 0

4 years ago

Read 2 more answers

Evaluate this expression for the given value of the variable 4 (d+7);d=-2

Paha777 [63]

Exact Form:

d

=

−

7

−

√

47

2

,

−

7

+

√

47

2

d

=

-

7

-

47

2

,

-

7

+

47

2

Decimal Form:

d

=

−

0.07217269

…

,

−

6.92782730

…

6 0

3 years ago

Read 2 more answers

A cylindrical tank with radius 3 m is being filled with water at a rate of 4 m3/min. How fast is the height of the water increas

Fittoniya [83]

Height of the water increasing is at rate of $#(dh)/(dt)=3/(25 pi)m/(min)#$

<h3>How to solve?</h3>

With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:

$#V=pi r^2 h#$

There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:

$#V=pi (5m)^2 h#$

Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:

$#(dV)/(dt)=(25 m^2) pi (dh)/(dt)#$

In the problem, we are given $#3(m^3)/min# which is #(dV)/(dt)#.$

So we need to substitute this in:

$#(dh)/(dt)=(3m^3)/(min (25m^2) pi)=3/(25 pi)m/(min)#$

Hence, Height of the water increasing is at rate of $#(dh)/(dt)=3/(25 pi)m/(min)#$

<h3>Formula used: </h3>

$#V=pi r^2 h#$

To Learn more visit:

brainly.com/question/4313883

#SPJ4

4 0

2 years ago

Read 2 more answers

7x^2=9+x what are the values of x<br><br>Will give medal and points

DENIUS [597]

7x² = 9 + x Subtract x from both sides
7x² - x = 9 Subtract 9 from both sides
7x² - x - 9 = 0 Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x = $\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ Plug in the a, b, and c values
x = $\frac{- (-1) \pm \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}$ Cancel out the double negative
x = $\frac{1 \pm \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}$ Square -1
x = $\frac{1 \pm \sqrt{1 - 4(7)(-9)} }{2(7)}$ Multiply 7 and -9
x = $\frac{1 \pm \sqrt{1 - 4(-63} }{2(7)}$ Multiply -4 and -63
x = $\frac{1 \pm \sqrt{1 + 252} }{2(7)}$ Multiply 2 and 7
x = $\frac{1 \pm \sqrt{1 + 252} }{14}$ Add 1 and 252
x = $\frac{1 \pm \sqrt{253} }{14}$ Split up the $\pm$
x = $\left \{ {{ \frac{1 + \sqrt{253} }{14} } \atop { \frac{1 - \sqrt{253} }{14} }} \right.$
The approximate square root of 253 is <span>15.905973.
</span>x ≈ $\left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right$ Add and subtract
x ≈ $\left \{ {{ \frac{16.905973}{14} } \atop { \frac{14.905973}{14} }} \right.$ Divide
x ≈ $\left \{ {{1.2075} \atop {1.0647}} \right.$ Round to the nearest hundredth
x ≈ $\left \{ {{1.21} \atop {1.06}} \right.$

<span>
</span>

7 0

3 years ago

Vikas is the head of student council this year at his high school in London. He is responsible for planning the annual graduatio

Naily [24]

Answer:

C = 600 + 50s

Step-by-step explanation:

The students are planning to visits the Canada's wonderland. The students will spend a full day at the park.

The entry fee for each student is $50 and the bus cost is $600. Each student will pay $50 for entry into the park.

Let

the number of student = s

cost of the trip = C

Relating the variable C and s

The total amount of money the student will pay for entry fee = 50 × s = 50s

Therefore, cost of the trip can be expressed as follows

C = 600 + 50s

8 0

3 years ago