<span>Use the distributive property to rewrite each algebraic expression: Do not solve, just rewrite.
1) 8(x + 7) = 8x + 56
2) 5(x - 10) = 5x - 50
3) 6(11 + x) = 66 + 6x
</span><span>Factor each expression. (Pull a common factor from each number)
COMPLETED EXAMPLE: 27 + 12 = 3(9 + 4) → (3 is the shared factor for 27 and 12)
4) 12 + 36 = 12 (1 + 3)
5) 16 + 20 = 4 (4 + 5)
Solve each expression using the distributive property.
6) 4 x 82 = 4 (80 + 2) = 320 + 8 = 328
7) 12 x 44 = 12 (40 + 4) = 480 + 48 = 528
</span><span>8) Mrs. S bought 9 folders and 9 notebooks. The cost of each folder was $2.50. Each notebook cost $4. First, write an expression for the problem then find the total cost.
Expression = 9f + 9n = 9($2.50) + 9($4)
Total cost =</span>9($2.50) + 9($4) = $22.5 + $36 = $58.5
Answer:
15
Step-by-step explanation:
x=25
Step-by-step explanation:
2000=400√x
Step 1: Flip the equation.
400√x=2000
Step 2: Divide both sides by 400.
400√x/400=2000/400
√x=5
Step 3: Solve Square Root.
√x=5
x=52(Square both sides)
x=25
Check answers. (Plug them in to make sure they work.)
x=25
Answer:
The equation in vertex form is:

Step-by-step explanation:
Recall that the formula of a parabola with vertex at
is given by the equation in vertex form:

where the parameter
can be specified by an extra information on any other point apart from the vertex, that parabola goes through.
In our case, since the vertex must be the point (2, 1), the vertex form of the parabola becomes:

we have the information on the extra point (0, 5) where the parabola crosses the y-axis. Then, we use it to find the missing parameter
:

The, the final form of the parabola's equation in vertex form is:

Answer:
The range for Problem 18 is

The range for problem 19 is

Step-by-step explanation:
To find the range you subtract the smallest value from the largest value. In problem 18 the largest value was 17.6 and the smallest was 1.5.

In problem 19 the largest value was 181 and the smallest was 14
