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guapka [62]
2 years ago
8

A car initially traveling at 20 kilometers per hour takes 10 seconds to speed up to 70 km/hour. At what rate is it changing spee

d?
Mathematics
1 answer:
Snezhnost [94]2 years ago
7 0
  • Initial velocity=u=20km/h
  • Final velocity=v=70km/h
  • Time=10s=t

Convert speeds to m/s

\\ \rm\longmapsto u=20\times\dfrac{5}{18}=5.05m/s

\\ \rm\longmapsto v=70\times \dfrac{5}{18}=19.4m/s

\boxed{\sf Acceleration=\dfrac{v-u}{t}}

\\ \rm\longmapsto Acceleration=\dfrac{19.4-5.05}{10}

\\ \rm\longmapsto Acceleration=\dfrac{14.3}{10}

\\ \rm\longmapsto Acceleration=143m/s^2

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The point (8, –15) is on the terminal side of an angle θ. What is sin θ ?
katen-ka-za [31]
Let's calculate the hypotenuse of this right triangle:

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a) If Ф is facing the largest side (15), then sinФ = opposite side / hypotenuse
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b) If Ф is facing the smallest  side (8), then sinФ = opposite side / hypotenuse
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7 0
3 years ago
Use the following problem to answer questions 8 and 9. A television manufacturer has three locations where it is finally assembl
Nonamiya [84]

Answer:

The probability of finding a non-defective television is 0.9815.

Step-by-step explanation:

We are given that a television manufacturer has three locations where it is finally assembled. Plants A, B, and C supply 65%, 15%, and 20% respectively of the televisions used by the manufacture.

Quality control has determined that 1.5% produced by Plant A are defective, while plants B and C have 2.5% defective products.

Let Probability that Plant A supply televisions = P(A) = 0.65

Probability that Plant B supply televisions = P(B) = 0.15

Probability that Plant C supply televisions = P(C) = 0.20

<em>Also, let D = event that television is defective</em>

Probability that television is defective given that it is supplied by Plant A = P(D/A) = 0.015

Probability that television is defective given that it is supplied by Plant B = P(D/B) = 0.025

Probability that television is defective given that it is supplied by Plant C = P(D/C) = 0.025

<u>Now, to find the probability of finding a non-defective television firstly we will find the probability of a defective television.</u>

<em>Probability of a defective television is given by;</em>

   =  P(A) \times P(D/A) + P(B) \times P(D/B) + P(C) \times P(D/C)  

   =  0.65 \times 0.015 + 0.15 \times 0.025 + 0.20 \times 0.025  

   =  0.00975 + 0.00375 + 0.005

   =  0.0185

Now, <em><u>probability of finding a non-defective television</u></em> = 1 - Pro<em>bability of a defective television</em>

Probability of finding a non-defective television = 1 - 0.0185

                                                                                   = 0.9815

<em>Therefore, the probability of finding a non-defective television is 98.15%.</em>

8 0
3 years ago
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Answer:

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Answer:

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6x+1-(3x-1)

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=3x+2

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2 years ago
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