Prime numbers basically numbers that dont have any numbers that will be multiplied to get to it. So, it would be:
23
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All the other numbers in between can be divided by something and not become a decimal. Other than 23, it can be divided by anything without becoming a decimal.
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<em>~Hope this helped :)</em>
Answer:
A, B, F
Step-by-step explanation:
2/3 - x + 1/6 = 6x
Collect like terms
2/3 + 1/6 = 6x + x
(4+1) / 6 = 7x
5/6 = 7x
x = 5/6 ÷ 7
= 5/6 × 1/7
x = 5/42
a) 4 - 6x + 1 = 36x
4 + 1 = 36x + 6x
5 = 42x
x = 5/42
Equivalent to the last step of the simplification above
b) 5/6 - x = 6x
5/6 = 6x + x
5/6 = 7x
This is equivalent to the third step of the simplification
c) 4 - x + 1 = 6x
4 + 1 = 6x + x
5 = 7x
x = 5/7
Not equivalent to any of the steps in the simplification above
d) 5/6 + x = 6x
5/6 = 6x - x
5/6 = 5x
x = 5/6 ÷ 5
= 5/6 × 1/5
x = 5/30
Not equivalent to any of the steps in the simplification above
e) 5 = 30x
x = 5/30
Not equivalent to any of the steps in the simplification above
f) 5 = 42x
x = 5/42
Equivalent to the last step of the simplification above
Answer:
length: 16 m; width: 13 m
Step-by-step explanation:
Write each of the statements as an equation. You know that the formula for the perimeter is ...
P = 2(L +W)
so one of your equations is this one with the value of P filled in:
• 2L + 2W = 58
The other equation expresses the relation between L and W:
• L = W +3 . . . . . . . . the length is 3 meters greater than the width
There are many ways to solve such a system of equations. Since you have an expression for L, it is convenient to substitute that into the first equation to get ...
2(W+3) +2W = 58
4W +6 = 58 . . . . . . . simplify
4W = 52 . . . . . . . . . . subtract 6
W = 13 . . . . . . . . . . . .divide by 4
We can use the expression for L to find its value:
L = 13 +3 = 16
The length is 16 meters; the width is 13 meters.
Answer:
The value of the test statistic is 
Step-by-step explanation:
Our test statistic is:

In which X is the sample mean,
is the expected value,
is the standard deviation and n is the size of the sample.
The level of ozone normally found is 7.5 parts/million (ppm).
This means that 
The mean of 24 samples is 7.8 ppm with a standard deviation of 0.7.
This means that 
Test Statistic:



The value of the test statistic is 