2. χΣ -4 Please help
1 answer:
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Assume that 
and <span>multiply the equation 
by 4p. Then you obtain the equation 
.
</span>
1) If k>0, then 4pk>0 and the equation doesn't have solutions, because <span>
and this is unreal.
</span>
<span>2) If k=0, then 4pk=0 and
. There is one solution x=h.
</span>
2) If k<0, then 4pk<0 and the equation
<span>
has two different solutions 
and 
.</span>
</span>
1) If k>0, then 4pk>0 and the equation doesn't have solutions, because <span>
</span>
<span>2) If k=0, then 4pk=0 and
</span>
2) If k<0, then 4pk<0 and the equation
<span>