With what also can I get brainiest?
Extraneous solutions, is answers that we get because of squaring both sides of the radical equation, but in reality, they are not going to be the solutions of the given equation.
(√(4x+41))²=(x+5)²
4x+41=x²+10x+25
x²+6x-16=0
(x-2)(x+8)=0
x1=2 , x2=-8,
And now we must to check them by substitution into initial equation
√(4x+41)=x+5
1) x=2, √(4*2+41)=2+5, √49=7, 7=7 true
2) x=-8, √(4*(-8)+41)=-8+5, √9 =-3 false,
so an extraneous solution x=-8
We can solve this in 2 ways
Since a1 = 4
a2 = 4 * (3) = 12 i.e( a1* common ratio)
a3 = 12 * (3) = 36 i.e( a2 * common ratio)
a4 = 36 * (3) = 108 i.e( a3* common ratio)
a5 = 108 * (3) = 324 i.e(a4*common ratio)
and so on
The general equation of a circle, with radius R and center (h, k) is:
![(x-h)^2+(y-k)^2=R^2](https://tex.z-dn.net/?f=%28x-h%29%5E2%2B%28y-k%29%5E2%3DR%5E2)
Using the data given, the equation would be:
Answer:
Step-by-step explanation:
9/10+5/6 =
27/30+25/30 =
52/30 = 1 22/30 =1 11/15