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Blizzard [7]
3 years ago
12

Find the simplified ratio of 300ml in 5 minutes

Mathematics
1 answer:
andriy [413]3 years ago
6 0
300ml in 5 min can be written as a fraction 300ml/5min or 300/5 ml per min. 300/5 is the same as 60/1

So 300ml / 5min = 60ml/1min
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Solve the linear equation<br><br> <img src="https://tex.z-dn.net/?f=4%5E%7Bx%2B7%7D%20%3D%208%5E%7B2x-3%7D" id="TexFormula1" tit
GREYUIT [131]

Answer:

x = 5.75

Step-by-step explanation:

4^(x+7) = 8^(2x-3)

But; 4^(x+7) = 2^2(x+7)

8^(2x-3) = 2^3(2x-3)

2^2(x+7) = 2^3(2x-3)

Since the bases are the same;

2(x+7) = 3(2x-3)

2x + 14 = 6x -9

14 + 9 = 6x - 2x

23 = 4x

x = 23/4

<u>x = 5.75</u>

3 0
3 years ago
Please help :) ...........
ad-work [718]
I think the 3rd one idk wait for someone else to answer go compare
5 0
3 years ago
What is 1/10 of 209? Enter your answer in the box as a decimal.
VMariaS [17]

Answer:

20.9

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The wildlife department has been feeding a special food to rainbow trout fingerlings in a pond. based on a large number of obser
Liono4ka [1.6K]
The normal distribution curve for the problem is shown below

We need to standardise the value X=405.5 by using the formula

z-score= \frac{X-Mean}{Standard Deviation}
z-score= \frac{405.5-402.7}{8.8} =0.32

We now need to find the probability of z=0.32 by reading the z-table

Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

P(Z\ \textgreater \ z)=1 - P(Z\ \textless \ z)

from  the z-table, the reading P(Z\ \textless \ 0.32) gives 0.6255

hence, 
P(Z\ \textgreater \ 0.32)=1-0.6255=0.3475

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%

7 0
3 years ago
Helpppppp. Pleaseeeeeeeeeeee
Irina-Kira [14]
I think it’s 0.85d, but i’m not sure
7 0
3 years ago
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