Draw two planes that intersect in line ET I have no idea how to draw this please help me
1 answer:
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Answer:
<u><em>x = 4</em></u>
<u><em>x = 3</em></u>
<em><u>x = 10</u></em>
<u><em>x = 3</em></u>
<em><u>x = 16</u></em>
<em><u>x = 35</u></em>
Step-by-step explanation:
x · 10 = 5 · 8
10x = 40
10x ÷ 10 = 40 ÷ 10
<u><em>x = 4</em></u>
x · 8 = 12 · 2
8x = 24
8x ÷ 8 = 24 ÷ 8
<u><em>x = 3</em></u>
x · 3 = 15 · 2
3x = 30
3x ÷ 3 = 30 ÷ 3
<em><u>x = 10</u></em>
x · 12 = 6 · 6
12x = 36
12x ÷ 12 = 36 ÷ 12
<u><em>x = 3</em></u>
x · 2 = 8 · 4
2x = 32
2x ÷ 2 = 32 ÷ 2
<em><u>x = 16</u></em>
x · 2 = 10 · 7
2x = 70
2x ÷ 2 = 70 ÷ 2
<em><u>x = 35</u></em>
I have attached an image of the triangle.
BC = 9 cm
Answer:
CE = 7.2 cm
Step-by-step explanation:
In the attached triangle, we see that;
AB = AC = 7.5cm
BC = 9 cm
AD = 6cm
BC = 9cm
Formula for area of triangle is given as;
A = ½bh
Where b is base and h is height.
For the ∆ ABC with BC as base,
Area = ½ × 9 × 6 = 27 m²
Similarly, For ∆ ABC with AB as base,
Area = ½ × 7.5 × CE
Now, area from earlier is 27 cm²
Thus;
½ × 7.5 × CE = 27
Multiply both sides by 2 to get;
7.5CE = 54
CE = 54/7.5
CE = 7.2 cm
