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suter [353]
3 years ago
11

Simplify the expression 7g+4p-3g-9p

Mathematics
2 answers:
Svetach [21]3 years ago
6 0
I think it’s 4g-5p

7g, -3g and 4g are like terms!
otez555 [7]3 years ago
3 0

Answer:

4g-5p i think

Step-by-step explanation:

7g-3g=4g

4p-9p=-5p

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If 3 cups of rice serves 5 people, how many cups do you need to serve 13 people
elena-14-01-66 [18.8K]
First let's find out how many cups serve one person.

3 ÷ 5 = 1.6

1.6 of a cup serves one person.

1.6 × 13 = 20.8

It takes 20.8 (21 rounded) to serve 13 people.
3 0
3 years ago
Solve for x.
denis-greek [22]

Answer:

\frac{3\±\sqrt{3}}{3}

Step-by-step explanation:

Whe have the function 3x^2-6x+2=0

To solve this equation we must factor.

To factor, we need to find the points where the function is equal to zero. So we use the quadratic formula

\frac{-b\±\sqrt{b^2-4ac}}{2a}

Where:

a = 3

b = -6

c = 2

Then

\frac{-(-6) + \sqrt{(-6)^2-4(3)(2)}}{2(3)} = \frac{3+\sqrt{3}}{3}\\\\and\\\\\frac{-(-6) - \sqrt{(-6)^2-4(3)(2)}}{2(3)}= \frac{3-\sqrt{3}}{3}

finally the correct answer is  \frac{3\±\sqrt{3}}{3}

5 0
2 years ago
Read 2 more answers
Given the parent function p(x) = cos x, which
GaryK [48]

Answer: left a units, down b units

Step-by-step explanation:

5 0
2 years ago
Mathematics 13 don’t understand
UNO [17]

Answer:

  1/6^3

Step-by-step explanation:

The applicable rules of exponents are ...

  a^-b = 1/a^b

  (a^b)(a^c) = a^(b+c)

__

Your expression can be simplified as follows:

  \dfrac{6^{-5}}{6^{-2}}=\dfrac{1}{(6^{-2})(6^5)}=\dfrac{1}{6^{-2+5}}=\boxed{\dfrac{1}{6^3}}

_____

<em>Additional comment</em>

If you think of an exponent as signifying repeated multiplication, the rules of exponents may be easier to remember. The exponent tells you how many times the base is a factor in the product.

Consider multiplication:

  (x\cdot x\cdot x)\cdot(x\cdot x)=x^3\cdot x^2=x^{3+2}=x^5\\\\(x\cdot x\cdot x)\cdot(x\cdot x\cdot x)=(x^3)^2=x^{3\cdot2}=x^6

Consider division:

  \dfrac{x\cdot x\cdot x}{x\cdot x}=x\quad\Longleftrightarrow\quad\dfrac{x^3}{x^2}=x^{3-2}=x^1\\\\\dfrac{x\cdot x}{x\cdot x\cdot x}=\dfrac{1}{x}\quad\Longleftrightarrow\quad\dfrac{x^2}{x^3}=x^{2-3}=x^{-1}

This may help you see that a positive exponent in the denominator is equivalent to a negative exponent in the numerator (and vice versa).

6 0
2 years ago
What is the slope of the equation that is represented by the table below?
yuradex [85]

Answer:A

Step-by-step explanation:

You use the equation:

m= (y2-y1) ÷ ( x2-x1)

m= (12-9) ÷ (2-1)

m= 3÷1

m= 3

3 0
3 years ago
Read 2 more answers
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