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Degger [83]
3 years ago
12

Does anyone know how to finish this equation?

Mathematics
1 answer:
nikdorinn [45]3 years ago
6 0
Not sure what you mean?
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I need help pls can someone help pls
Julli [10]

= 23.5

hope it helps

8 0
3 years ago
Read 2 more answers
Solve the system of equations.<br> - 3x + 2y = 56<br> - 5 - 2y = 24
Oduvanchick [21]

Awnser

y=13

Step-by-step explanation:

-3x+2y=56

-5x-2y=24

so first we want to get rid of one variable, in this example we dont need to multiply because the y's cancel out

so we have

-8x=80

x=-10

now plug in x into an original equation

-3(-10)+2y=56

2y=26

y=13

hope that helps

4 0
3 years ago
Read 2 more answers
Help its difrrent question thx so much
irakobra [83]

Answer:

75% off

Step-by-step explanation:

I would personally say use a calculator, but whatever your instructor says.

First, do $600 off. You could also do 75% off first, but you choose. If you subtract $600 from $868, you get $268.

Next, do 75% off. If you take 100% - 75%, you get 25%, or 1/4. Multiply $868 by 1/4 and you get $217, which is the better deal.

So, to conclude, $217 is less than $268, and therefore 75% off is the better deal.

6 0
3 years ago
Read 2 more answers
Answer please? I'm struggling..​
klio [65]

Answer:

30

Step-by-step explanation:

you cant make both 3, 10, or 13, so it has to be 30. 10x3=30

6 0
3 years ago
Read 2 more answers
29. BASKETBALL When Jerald shoots a free throw, the ball is 6 feet from the floor and has
tatuchka [14]

Answer:

  a) j(t) = -16t^2 +20t +6

  b) 1 second

  c) less time

Step-by-step explanation:

The general equation for vertical motion is ...

  h(t)=-\dfrac{1}{2}gt^2+v_0t+h_0\\\text{where $v_0$ is the initial upward velocity, and $h_0$ is the initial height}

__

a) j(t) = -16t^2 +20t +6 . . . . . filling in the given initial values, with g=32 ft/s^2

__

b) We want to find the larger of the solutions to ...

  j(t) = 10 = -16t^2 +20t +6

Subtracting 6 and dividing by -4, we have ...

  -1 = 4t^2 -5t

  4t^2 -5t +1 = 0 . . . . add 1, put in standard form

  (4t -1)(t -1) = 0 . . . . . factor

  t = 1/4 or 1

The ball is in the air 1 second before reaching the hoop.

__

c) In generic terms, the equation of motion for a given shooting height at the same upward velocity will be ...

  10 = -16t^2 +20t + h0

  -16t^2 +20t +(h0 -10) = 0

Using the quadratic formula, we find the larger solution to be ...

  t = (-(20) -√(20² -4(-16)(h0 -10)))/(2(-16))

  t = (5/8) + √(64h0 -240)/32 = (5 +√(4h0 -15))/8

This value increases as h0 increases, so the ball will be in the air less time when Raymond shoots.

7 0
3 years ago
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