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borishaifa [10]
3 years ago
9

How many lines of symmetry does a hart have

Mathematics
2 answers:
SVEN [57.7K]3 years ago
5 0
A heart has only 1 line of symmetry. The one line is in the middle. I hope this helped.
balu736 [363]3 years ago
3 0
A heart has one line of symmetry, right down the middle.
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What is the answer I need help!!
Ganezh [65]
The correct answer is C
7 0
3 years ago
What is 4 1/2 x 6=? Simplify is possible divided by 2
allochka39001 [22]

Answer:

(i only solved for the equation)

27

Step-by-step explanation:

4 1/2= 9/2

9/2*6=27

8 0
2 years ago
Which equation is rewritten in vertex form
ser-zykov [4K]

Answer:

Option (2)

Step-by-step explanation:

Given expression is, y = (x + 3)² + (x + 4)²

By solving this expression,

y = x² + 6x + 9 + x² + 8x + 16

y = 2x² + 14x + 25

y = (2x² + 14x) + 25

y = 2(x² + 7x) + 25

y = 2[x² + 2(3.5x) + (3.5)² - (3.5)²] + 25

y = 2[x² + 2(3.5x) + (3.5)²] - 2(3.5)² + 25

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Therefore, Option (2) will be the vertex form.

6 0
3 years ago
Jena's income is $1600 a month, and she plans to budget 1/3 of her income for rent and 1/8 of her income for groceries. Step 2 o
WARRIOR [948]

Answer:

Jena spends $ 733. 33 on her rent and groceries  altogether per month.

Step-by-step explanation:

Jena's total income in a month= $1600

Here , expenditure on rent = (1/3) of her income

So, now one- third of her income $1600 is  

= \frac{1}{3}  \times 1600 = 533.33

or, (1/3) of her salary is  $533. 33

Hence, Jena spends $ 533. 33 on her rent monthly.

Now, her expenditure on groceries = (1/8) of her income

So, now one- eighth of her income $1600 is  

= \frac{1}{8}  \times 1600 = 200

or, (1/8) of her salary is $ 200.

Jena spends  $ 200. on her groceries  monthly.

So, Total expenditure  = Expenditure on rent + Expenditure on groceries

= $533. 33 + $200 = $733.33

Hence, Jena spends $ 733. 33 on her rent and groceries  altogether per month.

7 0
3 years ago
What is the equation, Harry weighs 30 lbs more than Ellen
Schach [20]
I am not to sure but I think it would be 30+n or a variable
6 0
3 years ago
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